Determine the design tensile strength of the 12 in. x 1/2 in. steel plate shown in the figure. The bolts are 3/4 in. diameter. The steel is A572 Gr. 50. Check yielding and fracture. Check Block Shear. T 3in. 1 3in 13in | 3in t
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- The given plate below with width of 200 mm andthickness of 16 mm is to be connected to two plates ofthe same width with half the thickness by 20 mmdiameter rivets as shown. The rivet hole is 2 mm greaterthan the rivet diameter. Allowable tensile stress on netarea is 0.6Fy. Allowable bearing stress is 1.35Fy. plate: fy = 241 mpa fu = 4141 mpa rivet: fv = 152 mpa a. Determine maximum load P without exceeding allowable tensile stress on plate b. Determine maximum load P without exceeding allowable shear stress on rivets c. Determine maximum load P without exceeding allowable bearing stress between plates and rivetsThe double - riveted joint connects two plates which are each 3.0 mm thick, and the rivets have a diameter of 4 mm., if the failure strength of the rivets in shear is 370 N/mm2 and the ultimate tensile strength of the plate is 465 N/mm?, determine the necessary rivet pitch b (mm) if the joint is to be designed so that failure due to shear in the rivets and failure due to tension in the plate occur simultaneously. Calculate also the joint efficiency n (%). 3 mm 4 mm diameterA single unequal angle 100 x 75 x 6 is connected to a 10 mm thick gusset plate at the ends with six 16 mm diameter bolts to the 100 mm of leg to transfer tension as shown in figure. What will be the block shear strength (in kN) of the angle section assuming that the yield and the ultimate stress of steel used are 250 MPa and 410 MPa respectively? ISA (100 × 75 x 6) -T 16 mm o bolt 10 mm 40 mm 40 mm| 40 mm 40 mm 40 mm 40 mm 10 mm
- 8 ksi, oy The normal stresses at a point in a steel member are ox 10 ksi. Using E -4 ksi, 29 x 103 ksi and v = 0.3, determine the normal strains at 2.31 %3D and oz this point. %3D ר- The rectongulor block, of material of€ length Land cross sectional ore 1 fitsA plate with width of 300mm and thickness of 20mm is to be connected between two plates 12mm thick with same width by 4-25mm diameter rivets a shown. The rivet holes have a diameter 2mm larger than the rivet diameter. The plate is A36 steel with yield strength Fy=248 Mpa and Fu-400MPa. The rivets have nominal shear stress capacity of 165MPa. O 803 O 1490 • Determine maximum load (P1) that can be applied without exceeding design tensile stress in plates (consider yielding and rupture of plates ONLY) in KN O 1180 O 1340 ο ο ο ο ο P3 O 1968 O 590 O 670 O 893 O 707 OO 150 O 1180 P1 P21. Two plates each with thickness 7-160mm are bolted together with 6-22 mm dia. bolts forming Bolt 52= 80mm spacing are as follows S₁ = 40mm Bolt hole dia. 25mm S3 = 100mm L fu- 483 тра ту- 345 тра Solve the allowable istrength and the P a Ultimate strength in: 1- Yielding 2. Rupture 3. Shear 4. Block Shear oo lap connection atat
- Maxinnun allowable stress for steel - 140 MPa Maxinnum allowable stress for ahuminum = 90 MPa Maxinnun allowable stress for brouze - 100 MPa Required: Maximun safe value of axial load P Aluminum A 400 mm Bronze A= 200 mm Steel A= 500 mm 2P 4P 2.5 m 2.0 m 1.5m2-A teel ptd is streteky between fwo rigid walls ard carries a tensile load f GO0ON at c f the alowate Stress is not to exceed 130 MPa at -4C, what is the minimum diameter f as ard E= J00 GPa. the nod? Figuro: ST L4.) A thin plate PQR is deformed so that the corner Q is displaced downward 1.0 mm to new position Q' as shown. Determine the shear strain at Q' associated with the two edges. 5) A pin mado of steo1 ie insorted in o short hanging TAOodon mombor ond iG 1used to Supnort lond E - 20
- A 20-mm-thick plate is bolted to the flange of a T-beam to form a 200 mm 20 mm built-up beam. If the beam is subjected to a vertical shear force of V = 200 kN, determine (a) the maximum shear stress in the beam, 10 mm 300 mm (b) the required spacing s of the bolts. The diameter of each bolt is 19 mm, and the allowable average shear stress in the bolts is 140 MPa. 10 mm42 KN the cross-sectional area of each member is 600 mm² Determine the stress in member EF. Answer in MPa rounded-off to 2 decimal places AddSNUIF ana. 2m A Last saved 4:09:09 PM 1455 ET 2 m Next > Last >A plate with width of 300 millimeters and thickness of 20 milimeters is to be connected to two plates of the same width with half the thickness by 25 millimeters by 25 millimeters diameter rivets. The rivets holes have a diameter 2 millimeters larger than the rivetdiameter. The plate is A36 with yield strength F, = 248MP.. Allowable tensile stress on net area is 0.6Fy and allowable bearing stress of 1.3Fy. The rivets are A502, Grade 2, hot-driven rivets with allowable shear stress of 150MPA. 1. Detemine the maximum load that can be applied to the connection with consideration to the yielding failure in the plates. 2. Detemine the maximum load that can be applied to the connection with consideration to the fracture failure in the plates. 3. Detemine the maximum load that can be applied to the connection without exceeding the allowable shearing stress in the rivets. 4. Detemine the maximum load that can be applied to the connection without exceeding the allowable bearing stress between…