Concept explainers
Express the volume flow rate of the duct in
Answer to Problem 27P
The volume flow rate of the duct in
Explanation of Solution
Given data:
Refer to the Figure problem 8.27 in the textbook for the duct system.
Formula used:
Write the expression for the volume flow rate.
Here,
Calculation:
Substitute
Give the volume flow rate in
Convert the unit volume flow rate in equation (2) from
Convert the unit volume flow rate in equation (2) from
Find the average speed of air in the
Substitute
Conclusion:
Hence, the volume flow rate of the duct in
Want to see more full solutions like this?
Chapter 8 Solutions
ENGINEERING FUNDAMENTALS
- Consider the duct system shown in the accompanying figure. The air flows from the 8"x12" duct into a 4"x6" duct steadily. The average speed of the air in the 4"x6" duct is 30 ft/s. What is the volume flow rate of air in the 8"x12" duct? Express the volume flow rate in ft3/s, ft3/min, and m3/s. What is the average speed of air in the 8"x12" duct? 4" x 6" V2 8" x 12" V1 Cross-sectional Area of 4"x6" = 24 in? %3D Cross-sectional Area of 8"x12" = 96 in? %3D V2 = 30 ft/s Recall: Q (Flow rate) = (ave. speed) (cross-sectional area)arrow_forwardA fluid (s=0.92) flows through a 97 mm diameter pipe at a velocity of 4 m/sec. Compute the Volume flow rate. (m3/s) Round your answer to 4 decimal places.arrow_forwardA hair dryer is basically a duct of constant diameter in which a few layers of electric resistors are placed. A small fan pulls the air in and forces it through the resistors where it is heated. If the density of air is 1.2 kg/m3 at the inlet and 1.05 kg/m3 at the exit, determine the percent increase in the velocity of air as it flows through the hair dryer. 1.05 kg/m³ Pin kg/m³ The increase in velocity is | %.arrow_forward
- A hair dryer is basically a duct of constant diameter in which a few layers of electric resistors are placed. A small fan pulls the air in and forces it through the resistors where it is heated. If the density of air is 1.16 kg/m³ at the inlet and 1.05 kg/m³ at the exit, determine the percent increase in the velocity of air as it flows through the hair dryer. 1.05 kg/m³ The increase in velocity is Pin kg/m³ 9.52 %.arrow_forwardAir enters this square duct at section 1 with the velocity distribution as shown. Note that the velocity varies in the y direction only ( for a given value of y, the velocity is the same for all values of z). What is the volume rate of flow? What is the mean velocity in the duct? What is the mass rate of flow if the mass density of the air is 1.2 kg/m cube?arrow_forwardCalculate the mass flow rate of air in g/min.arrow_forward
- A room has a volume of 120 ?3. An air-conditioning system is to replace the air in this room every twenty minutes, using ducts that have a square cross section. Assuming that air can be treated as an incompressible fluid, find the length of a side of the square if the air speed within the ducts is:a) 3.0 m/s and b) 5.0 m/s.arrow_forwardThe Venturi meter shown in the sketch below, contracts the flow down to one quarter of its original area. Cold air at 0 deg C flows in the pipe through the Venturi meter. The velocity of the air upstream of the Venturi meter is equal to 40 ft/s and the pressure at the same point is equal to 30 psia. What is the manometer reading if the fluid of the manometer is water with density 1000 kg/m3 . Assume that the air behaves as an ideal gas with molecular weight equal to Mw=29 kg/kmol and constant density evaluated at upstream conditions. Use Bernoulli's equation for your calculations. please respond asap!arrow_forwardA rectangular duct with dimensions of 1 m × 110 cm delivers conditioned air with a density of 1.2 kg⁄m3 to a room at a rate of 45 m3 /min. What is the mass-flow rate of air? What is the average air speed in the duct?arrow_forward
- Water flows from the ground floor to the third floor in a 4-storey building through a pipe 50 mm in diameter at a rate of 2 L/s and according to the diagram below. The water flows out from the system through a tap with an opening diameter of 15 mm. Q1. Calculate the energy loss due to friction as the water flows through the pipe (J/Kg) Q2. Calculate the total energy loss due to friction through the system (J/Kg) Q3. Calcualte the pressure at point 1 (kN/m2)arrow_forwardA tank contains gasoline and glycerine with open piezometer tubes attached as shown. The depths of fluids inside the tank are 2 m for air, 1.5 m for gasoline, 1 m for glycerine. The air pressure measured by the gage is 1.5 kPa. Unit weights are 6670 N/m3 for gasoline and 12360 N/m3 for glycerine. Air Gasoline Glycerine 6.0 Find the height of gasoline in the tube measured from the gasoline-glycerine interface. a.) 1.72 m b.) 1.22 m c.) 0.22 m d.) 2.72 m 7.0 Find the height of glycerine in the tube measured from the air-gasoline interface. a.) 0.93 m b.) 0.43 m c.) 0.57 m d.) 1.93 m e.)arrow_forwardA fluid flowing through a pipe of diameter 450 mm with velocity 3 m/s is divided into two pipes of diameters 300 mm and 200 mm. The velocity of flow in 300 mm diameter pipe is 2.5 m/s, then the velocity of flow through 200 mm diameter pipe will bearrow_forward
- Engineering Fundamentals: An Introduction to Engi...Civil EngineeringISBN:9781305084766Author:Saeed MoaveniPublisher:Cengage Learning