Physics for Scientists and Engineers: A Strategic Approach, Vol. 1 (Chs 1-21) (4th Edition)
Physics for Scientists and Engineers: A Strategic Approach, Vol. 1 (Chs 1-21) (4th Edition)
4th Edition
ISBN: 9780134110684
Author: Randall D. Knight (Professor Emeritus)
Publisher: PEARSON
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Chapter 28, Problem 1CQ

Rank in order, from largest to smallest, the currents I a to I d through the four resistors in FIGURE Q28.1.

Chapter 28, Problem 1CQ, Rank in order, from largest to smallest, the currents Iato Id through the four resistors in FIGURE

Expert Solution & Answer
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To determine

The rank in order of currents from largest to smallest

Answer to Problem 1CQ

Solution:

The rank in order of currents from largest to smallest is Ic>Ia=Id>Ib

Explanation of Solution

Given Info:

Voltage = Va=2.0Ω

Resistance= Ra=2.0Ω

Current = Ia=?

Voltage = Vb=1.0Ω

Resistance= Rb=2.0Ω

Current = Ib=?

Voltage = Vc=2.0Ω

Resistance= Rc=1.0Ω

Current = Ic=?

Voltage = Vd=1.0Ω

Resistance= Rd=1.0Ω

Current = Id=?

Formula:

Ohm’s law => I=VR ------ (1)

Applying eqn(1) to all the sets, we get

Ia=VaRa -------- (2)

Ib=VbRb -------- (3)

Ic=VcRc -------- (4)

Id=VdRd -------- (5)

Calculation:

Substituting the given data in eqn(2)

Ia = 1 A

Substituting the given data in eqn(3)

Ib = 0.5 A

Substituting the given data in eqn(4)

Ic = 2 A

Substituting the given data in eqn(5)

Id = 1 A

On comparing the above values, we get the required relation is Ic>Ia=Id>Ib

Conclusion:

The rank in order of currents from largest to smallest is Ic>Ia=Id>Ib

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Chapter 28 Solutions

Physics for Scientists and Engineers: A Strategic Approach, Vol. 1 (Chs 1-21) (4th Edition)

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