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Concept explainers
(a)
Boulder will land on the road or beyond if
![Check Mark](/static/check-mark.png)
Answer to Problem 13.173P
The horizontal distance travelled by the rock is
Explanation of Solution
Given information:
Rock A falls from a distance of
The total linear momentum of two particles is conserved. Therefore
The co-efficient of restitution is defined as
For a uniformly accelerated motion
In above equation
Calculation:
Assume
Apply conservation of linear momentum in direction t.
Substitute
Apply co-efficient of restitution equation in direction n.
Substitute
Velocity
Velocity in y direction
Assume t as the time that takes for the rod to reach the ground.
Substitute
Solve
Find the horizontal distance
Substitute
Conclusion:
The horizontal distance travelled by the rock is
(b)
Boulder will land on the road or beyond if
![Check Mark](/static/check-mark.png)
Answer to Problem 13.173P
The horizontal distance travelled by the rock is
Explanation of Solution
Given information:
Rock A falls from a distance of
The total linear momentum of two particles is conserved. Therefore
The co-efficient of restitution is defined as
For a uniformly accelerated motion
In above equation
Calculation:
Assume
Apply conservation of linear momentum in direction t.
Substitute
Apply co-efficient of restitution equation in direction n.
Substitute
Velocity
Velocity in y direction
Assume t as the time that takes for the rod to reach the ground.
Substitute
Solve
Find the horizontal distance
Substitute
Conclusion:
The horizontal distance travelled by the rock is
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Chapter 13 Solutions
Vector Mechanics For Engineers
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- Two steel blocks slide without friction on a horizontal surface. Their velocities before the impact are shown. Knowing that e = 0.75, determine their velocities after impact.arrow_forward1 2 2 blocks of ice are sliding on frictionless ice in opposite directions collide. The 1st block's mass is 3kg. It is moving to the right at 3 m/s. The 2nd block's mass is 2kg. It is moving to the left at 2 m/s. After the impact, the 2nd block moves to the right with a speed of 2 m/s What is the coefficient of restitution? m1 = 3 vla= 3 m2 = 2 v2a= -1 After collision: v2b=2 Momentum_a= m1*vla + m2*v2a v1b = (Momentum_a - m2*v2b) / m1 % Restitution equation e = (v2b - v1b) / (v1a - v2a)arrow_forward... Two blocks A and B of the same mass 0.93 kg are released from rest on a 26.3° incline when they are S = 10.8 m apart, as shown. The coefficient of friction under the upper block A is 0.16, and that under the lower block B is 0.33. Compute the distanced travelled by block B (in m) until the blocks touch each other. Round off only on the final answer expressed in 3 decimal places. blocks.png B A 8. E'arrow_forward
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