University Physics Volume 1
18th Edition
ISBN: 9781938168277
Author: William Moebs, Samuel J. Ling, Jeff Sanny
Publisher: OpenStax - Rice University
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Textbook Question
Chapter 13, Problem 38P
Using the average distance of Earth from the Sun, and the orbital peirod of Earth, (a) find the centripetal acceleration of Earth in its motion about the Sun. (b) Compare this value to that of the centripetal acceleration at the equator due to Earth’s rotation.
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Knowing the force of gravity for Earth, let's find out how fast Earth needs to go around the Sun, assuming uniform circular motion.
Take the Force of Gravity and divide it by the mass of the Earth
(This is the gravitational acceleration, or centripetal acceleration, of the Earth toward the Sun)
Use this centripetal acceleration and the data from the table above to calculate the velocity of the Earth. (Answer in m/s)
A 5kg object is in uniform circular motion traveling a circular path of radius 1.2m with a speed of 23m/s. (a) What is the objects centripetal acceleration? (b) What centripetal force is necessary to keep the object in this circular path?
(a) Using the average distance of Venus from the Sun and the orbital period of Venus, find the centripetal acceleration (in m/s) of Venus in its motion about the Sun. (Assume the orbit is circular. Enter the magnitude.)
m/s?
(b) Compare this value to the magnitude of the centripetal acceleration at the equator due to Venus's rotation.
dc, Venus about Sun
a
dc, equator
Chapter 13 Solutions
University Physics Volume 1
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