Concept explainers
Ethanol (C2H5OH) bums in air:
C2H5OH(l) + O2(g) → CO2(g) + H2O)(l)
Balance the equation and determine the volume of air in liters at 45.0°C and 793 mmHg required to burn 185 g of ethanol. Assume that air is 21.0 percent O2 by volume.
Interpretation:
The given equation has to be balanced and the volume of air in liters has to be calculated.
Concept Introduction:
Ideal gas is the most usually used form of the ideal gas equation, which describes the relationship among the four variables P, V, n, and T. An ideal gas is a hypothetical sample of gas whose pressure-volume-temperature behavior is predicted accurately by the ideal gas equation.
A balanced equation is an equation for a chemical reaction in which the number of atoms for each element in the reaction and the total charge are the similar for both the reactants and the products.
Answer to Problem 11.89QP
The balanced equation given by
The volume of air was found to be
Explanation of Solution
Unbalance equation
Carbon is balanced by multiplying 2 in product side
Next Oxygen is balance by multiplying 3 in reactant side
Finally Oxygen and Hydrogen is balance
To determine the moles of each reactant by multiplying 3 in product side
Hence the balanced equation given by
To calculate the moles of
The moles of
To determine the volume of
The volume of
To determine air is 21.0 percent
The volume of air is calculated by plugging in the values of the given volume of
The given equation was balanced and the volume of air in liters was calculated.
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Chapter 11 Solutions
Chemistry: Atoms First
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