Chemistry In Context
Chemistry In Context
9th Edition
ISBN: 9781259638145
Author: Fahlman, Bradley D., Purvis-roberts, Kathleen, Kirk, John S., Bentley, Anne K., Daubenmire, Patrick L., ELLIS, Jamie P., Mury, Michael T., American Chemical Society
Publisher: Mcgraw-hill Education,
bartleby

Concept explainers

bartleby

Videos

Textbook Question
Book Icon
Chapter 8, Problem 29Q

In each pair below, the [H+] is different. By what factor of 10 is it different?

  1. a. pH = 6 and pH = 8
  2. b. pH = 5.5 and pH = 6.5
  3. c. [H+] = 1 × 10−8 M and [H+] = 1 × 10−6 M
  4. d. [OH] = 1 × 10−2 M and [OH] = 1 × 10−3 M

(a)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation:

By what factor of 10 will be different for the given pair has to be determined.

Concept introduction:

The pH of a solution is a figure that expresses the acidity or the alkalinity of a given solution. pH is the concentration of hydrogen ion is measured using pH scale. The acidity of aqueous solution is expressed by pH scale.

  pH=log10[H+]

The difference in pH is by one unit, then the change in [H+] is by 10 times.

Explanation of Solution

Given pH of the solutions are pH = 6 and pH = 8.

The pH difference between the two solutions is 2.

pH of the solution can be calculated using the given equation,

  pH=log10[H+]

The difference in pH is by one unit, then the change in [H+] is by 10 times.

Therefore, solution having pH = 6 is100 times more [H+] than the solution having pH = 8.

(b)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation:

By what factor of 10 will be different for the given pair has to be determined.

Concept introduction:

The pH of a solution is a figure that expresses the acidity or the alkalinity of a given solution. pH is the concentration of hydrogen ion is measured using pH scale. The acidity of aqueous solution is expressed by pH scale.

  pH=log10[H+]

The difference in pH is by one unit, then the change in [H+] is by 10 times.

Explanation of Solution

Given pH of the solutions are pH = 5.5 and pH = 6.5.

The pH difference between the two solutions is 1.

pH of the solution can be calculated using the given equation,

  pH=log10[H+]

The difference in pH is by one unit, then the change in [H+] is by 10 times.

Therefore, solution having pH = 5.5 is10 times more [H+] than the solution having pH = 6.5.

(c)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation:

By what factor of 10 will be different for the given pair has to be determined.

Concept introduction:

The pH of a solution is a figure that expresses the acidity or the alkalinity of a given solution. pH is the concentration of hydrogen ion is measured using pH scale. The acidity of aqueous solution is expressed by pH scale.

  pH=log10[H+]

Explanation of Solution

Given that [H+] = 1×108M and [H+] = 1×106M.

pH of the solution can be calculated using the given equation,

  (i)  pH=log10[H+]=log10(1×108M)= 8(ii)  pH=log10[H+]=log10(1×106M)= 6

The pH difference between the two solutions is 2.

The difference in pH is by one unit, then the change in [H+] is by 10 times.

Therefore, solution having [H+] = 1×106M is100 times more [H+] than the solution having [H+] = 1×108M.

(c)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation:

By what factor of 10 will be different for the given pair has to be determined.

Concept introduction:

The pH of a solution is a figure that expresses the acidity or the alkalinity of a given solution. pH is the concentration of hydrogen ion is measured using pH scale. The acidity of aqueous solution is expressed by pH scale.

  pH=log10[H+]

The difference in pH is by one unit, then the change in [H+] is by 10 times.

Relationship between [OH] and [H+] can be given as,

  [H+][OH] = 1×1014

Explanation of Solution

Given that [OH] = 1×102M and [OH] = 1×103M.

The difference in pH is by one unit, then the change in [H+] is by 10 times.

pH of the solution with [OH] = 1×102M can be calculated using the given equation,

  [H+][OH] = 1×1014[H+] = (1×1014)[OH]=  (1×1014)(1×102M)=1×1012MpH=log10[H+]=log10(1×1012M)= 12

pH of the solution with [OH] = 1×103M can be calculated using the given equation,

  [H+][OH] = 1×1014[H+] = (1×1014)[OH]=  (1×1014)(1×103M)=1×1011MpH=log10[H+]=log10(1×1011M)= 11

The pH difference between the two solutions is 1.

Therefore, solution having [OH] = 1×103M is10 times more [H+] than the solution having [OH] = 1×102M.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
V. Milk of magnesia has a pH of 10.2. What is the [OH] of milk of magnesia? a. 6.31 × 10-11 M pH= 162 =) pO H)= 3.8 +=10.2 pO H)=3.8 3D3.8 b. 1.58 × 104M -) log= c. 1.58 x 10-5 M d. 1.02 x 103 M e.)6.31 × 104 M
9. Which ion is the only negative ion produced by an Arbenius. base in water? A NO, C. OH D. H
8. [H+] = 0.000048 M, what is the [OH-]? 9. [OH-] = 7.6 x 10-³ M, what is the [H+]?

Chapter 8 Solutions

Chemistry In Context

Ch. 8.4 - Prob. 8.18YTCh. 8.4 - Prob. 8.19YTCh. 8.5 - Identify a recent drought or flood that caused...Ch. 8.5 - Prob. 8.22YTCh. 8.6 - Prob. 8.25YTCh. 8.6 - Prob. 8.26YTCh. 8.6 - Prob. 8.28YTCh. 8.7 - Prob. 8.30YTCh. 8.7 - Prob. 8.31YTCh. 8.7 - Prob. 8.32YTCh. 8.7 - Prob. 8.33YTCh. 8.7 - Prob. 8.35YTCh. 8.7 - Prob. 8.36YTCh. 8.8 - For each of the strong acids shown below, write a...Ch. 8.8 - Although the word acid may conjure up all sorts of...Ch. 8.8 - Prob. 8.39YTCh. 8.9 - For each acidbase pair, write a balanced...Ch. 8.9 - Prob. 8.42YTCh. 8.9 - Prob. 8.43YTCh. 8.10 - Skill Building Small Changes, Big Effects Compare...Ch. 8.10 - Prob. 8.47YTCh. 8.10 - Prob. 8.48YTCh. 8.11 - In 2008, a group of scientists met in Monaco to...Ch. 8.11 - Prob. 8.50YTCh. 8.12 - Skill Building Water Treatment Chemicals a. Write...Ch. 8.12 - Prob. 8.52YTCh. 8.12 - Prob. 8.53YTCh. 8.12 - Prob. 8.54YTCh. 8.12 - Prob. 8.55YTCh. 8.13 - Prob. 8.56YTCh. 8.13 - Prob. 8.57YTCh. 8.13 - Prob. 8.58YTCh. 8.13 - Prob. 8.59YTCh. 8 - Your Turn 8.1 You Decide Opposites Attract Examine...Ch. 8 - Prob. 8.2YTCh. 8 - In any language, water is the most abundant...Ch. 8 - Prob. 2QCh. 8 - Prob. 3QCh. 8 - Prob. 4QCh. 8 - The following are four pairs of atoms. Consult...Ch. 8 - Prob. 6QCh. 8 - Prob. 7QCh. 8 - Both methane (CH4) and water are compounds of...Ch. 8 - Prob. 9QCh. 8 - Prob. 10QCh. 8 - a. Draw the Lewis structure for the water...Ch. 8 - Prob. 12QCh. 8 - Prob. 13QCh. 8 - Prob. 14QCh. 8 - Based on your experience, how soluble is each of...Ch. 8 - Prob. 16QCh. 8 - NaCl is an ionic compound, but SiCl4 is a...Ch. 8 - Prob. 18QCh. 8 - Prob. 19QCh. 8 - Prob. 20QCh. 8 - Prob. 21QCh. 8 - Prob. 22QCh. 8 - Prob. 23QCh. 8 - For a 2.5 M solution of Mg(NO3)2, what is the...Ch. 8 - Prob. 25QCh. 8 - Prob. 26QCh. 8 - Classify the following aqueous solutions as...Ch. 8 - Prob. 28QCh. 8 - In each pair below, the [H+] is different. By what...Ch. 8 - Which of these has the lowest concentration of...Ch. 8 - Consider these ions: nitrate, sulfate, carbonate,...Ch. 8 - Prob. 32QCh. 8 - Prob. 33QCh. 8 - Prob. 34QCh. 8 - Which gas is dissolved in water to produce each of...Ch. 8 - Prob. 36QCh. 8 - Prob. 37QCh. 8 - Prob. 38QCh. 8 - Use the Internet to determine which has the higher...Ch. 8 - Prob. 40QCh. 8 - Prob. 41QCh. 8 - Prob. 42QCh. 8 - At the edge of a favorite fishing hole, a new sign...Ch. 8 - Prob. 44QCh. 8 - A diatomic molecule XY that contains a polar bond...Ch. 8 - Prob. 46QCh. 8 - Prob. 47QCh. 8 - Prob. 48QCh. 8 - Prob. 49QCh. 8 - The unusually high specific heat of water helps...Ch. 8 - Prob. 51QCh. 8 - Prob. 52QCh. 8 - Prob. 53QCh. 8 - Prob. 55QCh. 8 - In 2005, the Great LakesSt. Lawrence River Basin...Ch. 8 - Liquid CO2 has been used successfully for many...Ch. 8 - Prob. 58QCh. 8 - Prob. 60QCh. 8 - Prob. 61QCh. 8 - Hard water may contain Mg2+ and Ca2+ ions. The...Ch. 8 - Suppose you are in charge of regulating an...Ch. 8 - Prob. 64QCh. 8 - Prob. 65QCh. 8 - Prob. 66QCh. 8 - Prob. 67QCh. 8 - List a recent theme for World Water Day. Prepare a...Ch. 8 - Prob. 69Q
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Chemistry: An Atoms First Approach
Chemistry
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Cengage Learning
Text book image
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Text book image
Introductory Chemistry: A Foundation
Chemistry
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Text book image
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Text book image
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Stoichiometry - Chemistry for Massive Creatures: Crash Course Chemistry #6; Author: Crash Course;https://www.youtube.com/watch?v=UL1jmJaUkaQ;License: Standard YouTube License, CC-BY
Bonding (Ionic, Covalent & Metallic) - GCSE Chemistry; Author: Science Shorts;https://www.youtube.com/watch?v=p9MA6Od-zBA;License: Standard YouTube License, CC-BY
General Chemistry 1A. Lecture 12. Two Theories of Bonding.; Author: UCI Open;https://www.youtube.com/watch?v=dLTlL9Z1bh0;License: CC-BY