To form a helium atom, an alpha particle that contains two protons and two neutrons is fixed at one location, and two electrons are brought in from far away, one at a time. The first electron is placed at 0.600 × 10 − 10 m from the alpha particle and held there while the second electron is brought to 0.600 × 10 − 10 m from the alpha particle on the other side from the first electron. See die final configuration below, (a) How much work is done in each step? (b) What is the electrostatic energy of die alpha particle and two electrons in the final configuration?
To form a helium atom, an alpha particle that contains two protons and two neutrons is fixed at one location, and two electrons are brought in from far away, one at a time. The first electron is placed at 0.600 × 10 − 10 m from the alpha particle and held there while the second electron is brought to 0.600 × 10 − 10 m from the alpha particle on the other side from the first electron. See die final configuration below, (a) How much work is done in each step? (b) What is the electrostatic energy of die alpha particle and two electrons in the final configuration?
To form a helium atom, an alpha particle that contains two protons and two neutrons is fixed at one location, and two electrons are brought in from far away, one at a time. The first electron is placed at
0.600
×
10
−
10
m from the alpha particle and held there while the second electron is brought to
0.600
×
10
−
10
m from the alpha particle on the other side from the first electron. See die final configuration below, (a) How much work is done in each step? (b) What is the electrostatic energy of die alpha particle and two electrons in the final configuration?
Alpha particles which have a charge +2e and mass 6.64 x 10-27 kg are initially at rest and are fired directly at a stationary lead nucleus (charge +82e) at a speed of 2.40 x 107 m/s. Determine the distance of closest approach (in fm) before the alpha particle reverses
direction. Assume the lead nucleus remains stationary. Assume the alpha particles are initially very far from a stationary lead nucleus.
An alpha particle (which has two protons) is sent directly toward a target nucleus containing 92 protons.The alpha particle has an initial kinetic energy of 0.48 pJ.What is the least center-to-center distance the alpha particle will be from the target nucleus, assuming the nucleus does not move?
One form of nuclear radiation, beta decay, occurs when a neutron changes into a proton, an electron and a neutral particle called a neutrino. When this change happens to a neutron within the nucleus of an atom, the proton remains behind in the nucleus while the electron and neutrino are ejected from the nucleus. The ejected electron is called a beta particle. One nucleus that exhibits beta decay is the isotope of hydrogen 3H, called tritium, whose nucleus consists of one proton (making it hydrogen) and two neutrons (giving tritium an atomic mass m = 3u). Tritium is radioactive, and it decays to helium.
Suppose an electron is ejected from a 3H atom, which has a radius of 1.000×10-14 m. The resulting 3He atom has the same radius as the 3H atom. What is the escape velocity of the electron ejected from the process?
Note: Your answer may be larger than the speed of light which is okay in this scenario. To solve this problem correctly we would need to use special relativity.
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