Physics for Scientists and Engineers with Modern Physics
10th Edition
ISBN: 9781337553292
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
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Chapter 41.3, Problem 41.1QQ
To determine
The process of photon incident on hydrogen atom.
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A hydrogen atom is in its ground state. Incident on the atom is a photon having an energy of 10.5 eV. What is the result? (a) The atom is excited to a higher allowed state. (b) The atom is ionized. (c) The photon passes by the atom without interaction.
Consider photons incident on a hydrogen atom.
(a) A transition from the n = 4 to the n = 7 excited-state requires the absorption of a photon of what minimum energy? eV(b) A transition from the n = 1 ground state to the
n = 6 excited state requires the absorption of a photon of what minimum energy?
eV
An electron within the hydrogen atom is excited from n1 to n4. The electron then "falls" back to ni in two steps (n4
->
n2, n2 -> n1). Which of the following statements is true about the light emitted during this process?
One photons will be emitted.
Two photons will be emitted.
O Three photons will be emitted.
Four photons will be emitted.
Chapter 41 Solutions
Physics for Scientists and Engineers with Modern Physics
Ch. 41.3 - Prob. 41.1QQCh. 41.3 - Prob. 41.2QQCh. 41.4 - Prob. 41.3QQCh. 41.4 - Prob. 41.4QQCh. 41.8 - Prob. 41.5QQCh. 41 - Prob. 1PCh. 41 - Prob. 2PCh. 41 - Prob. 3PCh. 41 - Prob. 4PCh. 41 - Prob. 5P
Ch. 41 - Prob. 6PCh. 41 - Prob. 7PCh. 41 - Prob. 8PCh. 41 - Prob. 9PCh. 41 - Prob. 10PCh. 41 - Prob. 11PCh. 41 - Prob. 13PCh. 41 - Prob. 14PCh. 41 - Prob. 15PCh. 41 - Prob. 16PCh. 41 - Prob. 17PCh. 41 - Prob. 18PCh. 41 - Prob. 19PCh. 41 - Prob. 20PCh. 41 - Prob. 21PCh. 41 - Prob. 23PCh. 41 - Prob. 24PCh. 41 - Prob. 25PCh. 41 - Prob. 26PCh. 41 - Prob. 27PCh. 41 - Prob. 28PCh. 41 - Prob. 29PCh. 41 - Prob. 30PCh. 41 - Prob. 31PCh. 41 - Prob. 32PCh. 41 - Prob. 33PCh. 41 - Prob. 34PCh. 41 - Prob. 35PCh. 41 - Prob. 36PCh. 41 - Prob. 37APCh. 41 - Prob. 39APCh. 41 - Prob. 40APCh. 41 - Prob. 41APCh. 41 - Prob. 42APCh. 41 - Prob. 44APCh. 41 - Prob. 45APCh. 41 - Prob. 46APCh. 41 - Prob. 47APCh. 41 - Prob. 49APCh. 41 - Prob. 50APCh. 41 - Prob. 51CPCh. 41 - Prob. 52CP
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- A hydrogen atom emits a photon that has momentum 6.813 × 10-27 kg⋅m/s. This photon is emitted because the electron in the atom falls from a higher energy level into the n = 1 level. What is the quantum number of the level from which the electron falls? Use values of h = 6.626 × 10-34 J·s, c = 2.998 × 108 m/s, and e = 1.602 × 10-1⁹ C. Number i 1 Bohr-model picture of photon emission Unitsarrow_forwardA hydrogen atom in an n = 2, l = 1, ml = -1 state emits a photon when it decays to an n = 1, l = 0, ml = 0 ground state. In the absence of an external magnetic field, what is the wavelength of this photon?arrow_forwardA photon interacts with a ground-state electron in a hydrogen atom and is absorbed. The electron is ejected from the atom and exhibits a de Broglie wavelength of 1.828×10-10. Determine the frequency (in Hz) of the interacting photon.arrow_forward
- What are the (a) energy, (b) magnitude of the momentum, and (c) wavelength of the photon emitted when a hydrogen atom undergoes a transition from a state with n = 4 to a state with n = 2? (a) Number 2.55 Units eV (b) Number 1.3617 Units kg-m/s or N-s (c) Number 4.865976353 Units This answer has no unitsarrow_forwardElectrically excited mercury atoms have particularly strong emission of 4.9 eV photons, corresponding to a transition of one of the atom’s electrons from a higher energy state to a lower. Mercury vapor absorbs light of this wavelength as well; the energy of the photon moves an electron from the lower state to the higher.It’s also possible to produce an excitation through other means. If an electron with a kinetic energy of 4.9 eV strikes a mercury atom, it can transfer energy, moving an electron in the mercury atom from the lower level to the higher. The electron loses kinetic energy in the process; this is an inelastic collision. Electrons with kinetic energies lower than this transition energy undergo elastic collisions, leaving their kinetic energy unchanged.This was the idea behind the Franck-Hertz experiment, a classic experiment of early-20th-century physics. The basic setup is illustrated in Figure P28.88a. A tube is filled with mercury vapor. A heated electrode emits…arrow_forwardElectrically excited mercury atoms have particularly strong emission of 4.9 eV photons, corresponding to a transition of one of the atom’s electrons from a higher energy state to a lower. Mercury vapor absorbs light of this wavelength as well; the energy of the photon moves an electron from the lower state to the higher.It’s also possible to produce an excitation through other means. If an electron with a kinetic energy of 4.9 eV strikes a mercury atom, it can transfer energy, moving an electron in the mercury atom from the lower level to the higher. The electron loses kinetic energy in the process; this is an inelastic collision. Electrons with kinetic energies lower than this transition energy undergo elastic collisions, leaving their kinetic energy unchanged.This was the idea behind the Franck-Hertz experiment, a classic experiment of early-20th-century physics. The basic setup is illustrated in Figure P28.88a. A tube is filled with mercury vapor. A heated electrode emits…arrow_forward
- An electron with kinetic energy of 12.50 eV hits a hydrogen atom in its ground state. (a)Sketch the hydrogen energy level diagram, showing the transition to all possible excited state. (b) Find all the possible kinetic energies of the outgoing electron. (c) In the same sketch as part (a), draw all possible transitions when the atom relaxes and emits a photon. (d) Find the wavelengths of all the possible emission photons.arrow_forwardA hydrogen atom in an n=2, I=1, m1 = -1 state emits a photon when it decays to an n=1 I=0, mI=0 ground state. If the atom is in a magnetic field in the + z direction and with a magnitude of 2.50 T, what is the shift in the wavelength of the photon from zero-field value?arrow_forwardProblem 4: A photon originally traveling along the x axis, with wavelength λ = 0.100 nm is incident on an electron (m = 9.109 x 10-31 kg) that is initially at rest. The x-component of the momentum of the electron after the collision is 5.0 x 10-24 kg m/s and the y-component of the momentum of the electron after the collision is -6.0 x 10-24 kg m/s. If the photon scatters at an angle + from its original direction, what is wavelength of the photon after the collision. h= 6.626 x 10:34 J·s and c = 3.0 x 108 m/s.arrow_forward
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