Set: Set is a data structure that is used for storing and processing non duplicate elements. It is an interface which extends collection and it is an unordered collection of objects. Set is implemented by LinkedHashSet, HashSet or a TreeSet. LinkedHash Set: In order to store its elements internally, the LinkedHashSet uses Linked HashMaps and it is an ordered version of HashSet that maintains a doubly-linked List across all elements. Hash Set: In order to store its elements internally, the HashSet uses HashMaps and it implements the Set interface, backed by a hash table which is actually a HashMap instance

Question

Want to see the full answer?

Answer 1

Question

Chapter 21.4, Problem 21.4.1CP

Program Plan Intro

Set:

Set is a data structure that is used for storing and processing non duplicate elements. It is an interface which extends collection and it is an unordered collection of objects.

Set is implemented by LinkedHashSet, HashSet or a TreeSet.

LinkedHash Set:

In order to store its elements internally, the LinkedHashSet uses Linked HashMaps and it is an ordered version of HashSet that maintains a doubly-linked List across all elements.

Hash Set:

In order to store its elements internally, the HashSet uses HashMaps and it implements the Set interface, backed by a hash table which is actually a HashMap instance

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Q: Convert this to sorted array #include<iostream> #include"Student.cpp" class StudentList { private: struct ListNode { Student astudent; ListNode *next; }; ListNode *head; public: StudentList(); ~StudentList(); int IsEmpty(); void Add(Student newstudent); void Remove(); void DisplayList(); }; StudentList::StudentList() { head=NULL; }; StudentList::~StudentList() { cout <<"\nDestructing the objects..\n"; while(IsEmpty()!=0) Remove(); if(IsEmpty()==0) cout <<"All students have been deleted from a list\n"; }; int StudentList::IsEmpty() { if(head==NULL) return 0; else return 1; }; void StudentList::Add(Student newstudent) { ListNode *newPtr=new ListNode; if(newPtr==NULL) cout <<"Cannot allocate memory"; else { newPtr->astudent=newstudent; newPtr->next=head; head=newPtr; } }; void StudentList::Remove() { if(IsEmpty()==0) cout <<"List empty on remove"; else { ListNode *temp=head;…

#include <iostream> using namespace std; int BinSearch(int arr[],int beg, int end, int key){ if(beg > end){ return -1; } else{ int mid = beg + (end - beg) / 2; if(arr[mid] == key){ return mid; } else if(key < arr[mid]){ return BinSearch(arr,beg,mid-1,key); } else{ return BinSearch(arr,mid+1,end,key); } }} int main(){ int arr[] = {1,2,3,4,5,6,7,8}; int n = sizeof(arr)/sizeof(arr[0]); int key; cout << "Enter the key to be searched: " << endl; cin >> key; int res = BinSearch(arr,0,n-1,key); (res == -1) ? cout << "Element is not present in array" : cout << "Element is present at index " << res; return 0;}Q: Remove Function in above algorithm

#include <stdio.h> int arrC[10] = {0}; int bSearch(int arr[], int l, int h, int key); int *joinArray(int arrA[], int arrB[]) { int j = 0; if ((arrB[0] + arrB[4]) % 5 == 0) { arrB[0] = 0; arrB[4] = 0; } for (int i = 0; i < 5; i++) { arrC[j++] = arrA[i]; if (arrB[i] == 0 || (bSearch(arrA, 0, 5, arrB[i]) != -1)) { continue; } else arrC[j++] = arrB[i]; } for (int i = 0; i < j; i++) { int temp; for (int k = i + 1; k < j; k++) { if (arrC[i] > arrC[k]) { temp = arrC[i]; arrC[i] = arrC[k]; arrC[k] = temp; } } } for (int i = 0; i < j; i++) { printf("%d ", arrC[i]); } return arrC; } int bSearch(int arr[], int l, int h, int key) { if (h >= l) { int mid = l + (h - l) / 2; if…