) hoom temp Key 2982 M & = permittivity free space 8.854× 10-12 F/M Ionic strength (I) = 1.00 x 10-5 mol/ Boltzmann Constant (K) = 1.38× 10-23 m² ks 5²k"" Avogadro # (NA) = 6.022× 1023 Mol Elementary Charge (e) = 1.602 × 10-19 c Permittivity of solvent (εr) = 78.5F/m Calculate Debye length free space ionic Strength Calculate 1.00 × 10 = Mol/L X 1,000/m-3 0.01.1/m3 Ap = √Er Eo KBT 2NA E² I Plug value in equation 78.5F/m x 8.85 X 10-12 x 1.38 × 10-23 X 298k 2 x 6.022 × 10-23 mo Numerator 78.5 x 8.854×10 Denominator 2 x 6.022 x 10 π x (1.602 × 10 - 19 (c) 2x1.00×105 16H26 971 A -12 = 6.95 X10 -10 -23 -30 ✗ 1.38X10 X 298K = 2.86 x 10 -38 2.57 X10 2 -65 -23 x (1.602 × 10-19) ² x 1.00 × 105 = 3.09_XID -30 2.86X10 = 3.09×10 -65 פו - 1.69 1.76-7 = 9.62×10-14 27

: The heat of dissociation per mole of gaseous water at 18 °C and 1 atm is 241750 J/mol. Calculate its value at 68 °C. H,0(g) → H2(9) + 0-(9) Data given are Cp(H20) = 33.56 JK-ªmol¬1 Cp(H2) = 28.83 JK-!mol-1 С- (0) %3D 29.12 Jк--mol-1 %3D

ality al, g. on te ew led ed in X= A solution was prepared by dissolving 140.0 g of KCl in 315 g of water. Calculate the mole fraction of KC1. (The formula weight of KCl is 74.6 g/mol. The formula weight of water is 18.0 g/mol.) Express the mole fraction of KCl to two decimal places. View Available Hint(s) Submit 5 ΑΣΦ Part B - Use the definition of molality 001 mol/ka 12 of 33 ? P Pearson Review I Constants I Periodic Table A solution was prepared by dissolving 140.0 g of KCl in 315 g of water. Calculate the molality of KC1. (The formula weight of KCl is 74.6 g/mol. The formula weight of water is 18.0 g/mol.) Express the concentration of KCl in molality to two decimal places. ▸ View Available Hint(s) >

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