10.53 Use the concept of source transformation to find V, in the circuit of Fig. 10.97. 492 www -j30 j40 m + 20/0° V(+ j20 ΖΩ www -120 V ° Figure 10.97 For Prob. 10.53.

Use the supernode technique to find I, in the circuit in the figure below. 12/6° V -j1 N 20 27 Q j2 n (a) Find the real part of I,. (b) Find the imaginary part of I,. (a) A (b) A

Problem 10.073 - Input impedance of an Op Amp If the input impedance is defined as Zin = Vs/ls, find the input impedance of the op amp circuit given below when R₁ = 11 kQ2, R₂ = 20 kQ2, C₁ = 10 nF, C₂ = 20 nF, and @= 5000 rad/s. Please report your answer so the magnitude is positive and all angles are in the range of negative 180 degrees to positive 180 degrees. C₁ V₂ I₂ R₁ www + Zin The value of Zin = R₂ www C₂ 9 ΚΩ.

Problem 10.025 - Mesh Analysis with voltage sources Determine the output current to in the circuit given below using mesh analysis, where Vs 17 cos(20) V. Please report your answer so the magnitude is positive and all angles are in the range of negative 180 degrees to positive 180 degrees. 40 2H The output current lo m 0.25 F 6 sin 2r V cos(21+ A

a) Calculate the magnitude of the input impedance ZT at f= 10 kHz.  b) Using the result from a, calculate the peak-to-peak value of the source current Is = I1 For ZT, I got 986.88∠-29.61° Also for Is, I got 8.11mA∠29.61° Can you check if I got these correct

For the circuit shown in the figure, find Zeq and use that to find current I. Let ω = 10 rad/s and V=12<0° V. 4Ω j20 Ω wwwm V | The value of Zeq=(91353 -j14 Ω 16 Ω j25 Ω 27.4695 ) Ω and current (t) = 0.415 | & cos(10t+ -71.60 – 9) mA.

A coil has an impedance of (50 + j70) Ω. A capacitor is connected in parallel in order to produce resonance. If the source voltage is 120 V, find the power drawn by the circuit.

10.3 This is Fundamentals of Electrical Circuit subject. and the topic is all about Sinusoidal Steady-State Analysis.please show understandable solution. no need explaining..

a) Given the sinusoidal voltage source in a linear o i) The amplitude of the voltage 6 UTM 5 U ii) The angular frequency TM & UTM 5 UTM 8 UTM UTM & UTM iv) The value of V, at 1 = 3 ms 5 UTM 5 UTM 8 [ D UTM 8 UTM 8 UTM UTM UTM & UT

(10/1) (20/1) IREF = 50µA The circuit above is PMOS current mirror with the W/L ratio in parenthesis. Calculate the current lout given that A=0.01, and the voltages are VDS1 = 0.3V and VDS2 = 0.4V. The answer must be in uA.