ORGANIC CHEMISTRY (LL) W/WILEYPLUS NEXT
ORGANIC CHEMISTRY (LL) W/WILEYPLUS NEXT
12th Edition
ISBN: 9781119664635
Author: Solomons
Publisher: WILEY
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Chapter SRP, Problem 19P

Give structures for compounds A–D. Compound D gives a strong IR absorption band near 1720  cm 1 , and it reacts with bromine by a mechanism that does not involve radicals.

Chapter SRP, Problem 19P, Give structures for compounds AD. Compound D gives a strong IR absorption band near 1720cm1, and it

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Treatment of benzoic acid (C6H5CO2H) with NaOH followed by 1-iodo-3methylbutane forms H. H has a molecular ion at 192 and IR absorptions at 3064, 3035, 2960−2872, and 1721 cm−1. Propose a structure for H.
Compounds B and C are isomers with molecular formula C5H9BrO2. The 1H NMR spectrum of compounds B and C are shown below. The IR spectrum corresponding to compound B showed strong absorption bands at 1739, 1225, and 1158 cm-1, while the spectrum corresponding to compound C have strong bands at 1735, 1237, and 1182 cm-1. 1.Based on the information provided, determine the structure of compounds B and C.  2.Assign all peaks in 1H NMR spectrum of compounds B and C.
As we will learn in Chapter 17, reaction of (CH3)2CO with LIC≡CH followed by H2O affords compound D, which has a molecular ion in its mass spectrum at 84 and prominent absorptions in its IR spectrum at 3600−3200, 3303, 2938, and 2120 cm−1. D shows the following 1H NMR spectral data: 1.53 (singlet, 6 H), 2.37 (singlet, 1 H), and 2.43 (singlet, 1 H) ppm. What is the structure of D?

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ORGANIC CHEMISTRY (LL) W/WILEYPLUS NEXT

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