MindTap Math, 1 term (6 months) Printed Access Card for Larson’s Calculus: An Applied Approach, 10th
10th Edition
ISBN: 9781305967120
Author: Larson, Ron
Publisher: Cengage Learning
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Chapter A5, Problem 29E
To determine
To calculate: The simplified form of the expression
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When a radical expression has its denominator
rationalized, we change the denominator so that it no
longer contains any radicals. Doesn't this change the
value of the radical expression? Explain.
Can someone please explain to me how the highlighted expotents came to be? Are we looking at Lowest common denomintor? what purpose does the additional exponents serve?
Please explain step by step.
Chapter A5 Solutions
MindTap Math, 1 term (6 months) Printed Access Card for Larson’s Calculus: An Applied Approach, 10th
Ch. A5 - Prob. 1CPCh. A5 - Prob. 2CPCh. A5 - Prob. 3CPCh. A5 - Prob. 4CPCh. A5 - Prob. 5CPCh. A5 - Prob. 6CPCh. A5 - Prob. 7CPCh. A5 - Prob. 1ECh. A5 - Prob. 2ECh. A5 - Prob. 3E
Ch. A5 - Prob. 4ECh. A5 - Prob. 5ECh. A5 - Prob. 6ECh. A5 - Prob. 7ECh. A5 - Prob. 8ECh. A5 - Prob. 9ECh. A5 - Prob. 10ECh. A5 - Prob. 11ECh. A5 - Prob. 12ECh. A5 - Prob. 13ECh. A5 - Prob. 14ECh. A5 - Prob. 15ECh. A5 - Prob. 16ECh. A5 - Prob. 17ECh. A5 - Prob. 18ECh. A5 - Prob. 19ECh. A5 - Prob. 20ECh. A5 - Prob. 21ECh. A5 - Prob. 22ECh. A5 - Prob. 23ECh. A5 - Prob. 24ECh. A5 - Prob. 25ECh. A5 - Prob. 26ECh. A5 - Prob. 27ECh. A5 - Prob. 28ECh. A5 - Prob. 29ECh. A5 - Prob. 30ECh. A5 - Prob. 31ECh. A5 - Prob. 32ECh. A5 - Prob. 33ECh. A5 - Prob. 34ECh. A5 - Prob. 35ECh. A5 - Prob. 36ECh. A5 - Prob. 37ECh. A5 - Prob. 38ECh. A5 - Prob. 39ECh. A5 - Prob. 40ECh. A5 - Prob. 41ECh. A5 - Prob. 42E
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- O * Dashboard Khan Academy *Powers of products & quotients x org/math/cc-eighth-grade-math/cc-8th-numbers-operations/cc-8th-exponent-properties/e/powers-of-products-and-q A ODay 4 (Thursday): Unit 4 L17 x Select the equivalent expression. (2*- y4) =? Choose 1 answer: 64 B 224 212 y12 Stuck? Watch a video or use a hint.arrow_forwardSimplify 75 + V12 – V108- O 11/3 O 7/3 – 5/5 V3 O 5/3-+ 2/3 – 6/3arrow_forwardwrite the expression (-7)*(-7)*5 *5 *5*5 using exponents?arrow_forward
- explain why we multiply the denominators and why we multiply the numerators. Discuss how you are interpreting 2/5 * 3/7 and how that firs with the definition of multiplication.arrow_forwardEXAMPI E 7 Simplify each expression. Assume that all variables represent positive real numbers. Write all answers using positive exponents only. a8/3a1/3 a? (a) 52/753/7 (b) (52/7)3 (c) (a2/363/2,6 (d) Strategy We will use the product, power, and quotient rules for exponents to simplify each expression. Why The familiar rules for exponents are valid for rational exponents. Solution (a) 52/753/7 = 52/7 + 3/7 Use the rule xmx" = xm + n. 2 3 5 = 55/7 Add: 7 (b) (52/7)3 = 5(2/7)(3) Use the rule (xm)" = xmn. = 56/7 Multiply: 극(3)-극(클) -윽 (c) (a2/3b1/2)6 = (a2/3)6(b1/2)6 = a12/366/2 Use the rule (xy)" = x^y^. Use the rule (xm)" = xmn twice. Simplify the exponents. a8/3a1/3 a? Use the rules xmx" = xm + n ut - n (d) a8/3 + 1/3 – 2 and %3D = a8/3 + 1/3 – 6/3 2 = 3 8 3 = a3/3 1 + 3 %D 3 3 3 = 1. 3arrow_forwardZoom in 4. Simplify the expression 9x2 4 A. 81x20 B. 81x11 C. 10x10 D. 9x10 ere to searcharrow_forward
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