One model for the spread of a rumor is that the rate of spread is proportional to the product of the fraction y of the population who have heard the rumor and the fraction who have not heard the rumor. (a) Write a differential equation that is satisfied by y. (b) Solve the differential equation . (c) A small town has 1000 inhabitants . At 8 am,80 people have heard a rumor. By noon half the town has heard it . At what time will 90% of the population have heard the rumor?
One model for the spread of a rumor is that the rate of spread is proportional to the product of the fraction y of the population who have heard the rumor and the fraction who have not heard the rumor. (a) Write a differential equation that is satisfied by y. (b) Solve the differential equation . (c) A small town has 1000 inhabitants . At 8 am,80 people have heard a rumor. By noon half the town has heard it . At what time will 90% of the population have heard the rumor?
Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter6: Vector Spaces
Section6.7: Applications
Problem 13EQ
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One model for the spread of a rumor is that the rate of spread is proportional to the product of the fraction y of the population who have heard the rumor and the fraction who have not heard the rumor.
(a) Write a
(b) Solve the differential equation .
(c) A small town has 1000 inhabitants . At 8 am,80 people have heard a rumor. By noon half the town has heard it . At what time will 90% of the population have heard the rumor?
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