Explanation Given: ∫ − 2 1 e x 2 d x , N=6 We will apply midpoint sum formula. ∫ a b f ( x ) d x ≅ Δ x ( f ( x 0 + x 1 2 ) + f ( x 1 + x 2 2 ) + f ( x 2 + x 3 2 ) + … + f ( x n − 2 + x n − 1 2 ) + f ( x n − 1 + x n 2 ) ) Where, Δ x = b − a n . Calculations: We are given f ( x ) = e x 2 , n = 6 , a = − 2 and b = 1 . First, we will find Δ x , for that we will plug n = 6 , a = − 2 and b = 1 into Δ x formula. Then, Δ x = 1 + 2 6 ⇨ Δ x = 1 2 Hence, our interval [-2, 1] is dividing into n=6 subintervals with length Δ x = 1 2 as: [ ( − 2 , − 3 2 ) , ( − 3 2 , − 1 ) , ( − 1 , − 1 2 ) , ( − 1 2 , 0 ) , ( 0 , 1 2 ) , ( 1 2 , 1 ) ] . Hence, we got x 0 = − 2 , x 1 = − 3 2 , x 2 = − 1 , x 3 = − 1 2 , x 4 = 0 , x 5 = 1 2 , x 6 = 1 . Now, we will calculate function’s value at midpoint of each interval. f ( x 0 + x 1 2 ) = f ( ( − 2 ) + ( − 3 2 ) 2 ) = f ( − 7 4 ) = e 49 16 = 21... To determine T N :

4th Edition

ISBN: 9781319323394

Author: Rogawski

Publisher: MAC HIGHER

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Chapter 8.8, Problem 12E

To determine

$M_{N}$

To determine

$T_{N}$ :

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Chapter 8.8, Problem 11E

Chapter 8.8, Problem 13E

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>14 D. 6. 4. Consider the table. Radical Value V216 V125 Find the value of x, y and z. 3D100 are X = -50 and x = 50. 3100 are X = -10 and x = 10 D is x= 10. DD is x = 50.

Chapter 8 Solutions

CALCULUS W/SAPLING ACCESS >IC<

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