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In Problems 1–8 use the method of undetermined coefficients to solve the given nonhomogeneous system.
3.
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First Course in Differential Equations (Instructor's)
- Problem 16 (#2.3.34).Let f(x) = ax +b, and g(x) = cx +d. Find a condition on the constants a, b, c, d such that f◦g=g◦f. Proof. By definition, f◦g(x) = a(cx +d) + b=acx +ad +b, and g◦f(x) = c(ax +b) + d=acx +bc +d. Setting the two equal, we see acx +ad +b=acx +bc +d ad +b=bc +d (a−1)d=(c−1)b That last step was merely added for aesthetic reasons.arrow_forwardUse (1) in Section 8.4 X = eAtc (1) to find the general solution of the given system. 1 X' = 0. X(t) =arrow_forwardProblem 2. Consider the equation: x?y"(x) – xy' +y = 0. Given that yı(x) = x is a solution of this equation. Use the method of reduction of order, find the second solution y2(x) of the equation so that y1 and y2 are linearly independent. (Hint: y2(x) should be given in the form y2(x) = u(x)y1(x). Substitute it into the equation to find u(x).) %3Darrow_forward
- 3. Solve the following using Two Phase Method MIN Z = x1 + x2 subject to 2x1 + x2 >= 4 x1 + 7x2 >= 7 and x1,x2 >= 0arrow_forward10. Find the general solution of the system of differential equations 3 -2 -2 d. X = -3 -2 -6 X dt 3 10 1 + 2tet + 3t?et + 4t°et 3 1 -3 Hint: The characteristic polymomial of the coefficient matrix is -(A- 4)²(A- 3). Moreover (:) 2 1 Xp(t) = t²et +t³et +t'e3t -1 -1 -3 is a particular solution of the system.arrow_forward(6) Solve the following system of ODES: x'+y'+x=-e- x+2y+2x+2y = 0 and x(0) = -1 and y(0) = 1 HINT: The s-space algebraic equations are s+1 -1/(s+1) 2K*} = s+2 2s+2 Y solve these equations to obtainarrow_forward
- Q. No. 11 The solution of the DE 3ry" + y/ – y = 0 (a) yı = rš[1 – {x +²+...], y2 = 1+x – 20² + ... (b) yı = a3[1 – r +a² + ...], y2 = 1+ 2x – 2x² + ... (c) yı = xš[1 – x + a² + ...], y2 =1+ 2x – 2x3 + ... (d) yı = [1 – x + x² + ...], y2 = 1+ 2x – 2x2 +... solve this and tick the correct optionarrow_forwardThis is the first part of a two-part problem. Let P = cos(6t) y(t) = |- (sin(6t)) | -6 sin(6t) , Y2(t) = -6 cos(6t) a. Show that y1 (t) is a solution to the system y = Py by evaluating derivatives and the matrix product (t) -6 0 Enter your answers in terms of the variable t b. Show that y2 (t) is a solution to the system y = Pj by evaluating derivatives and the matrix product y2(t) Enter your answers in terms of the variable t.arrow_forwardIf L(x)=mx+b is the linearization of the cube root of 3x+1 at x=333 , then b=arrow_forward
- Consider the system = (41%) (22) + (1) * น in which a is a constant (a) Determine the condition under which the system is controllable (b) For a 1 (i) Show that et4 = (cos(t)) sin(t)) cos(t)) (Hint: You may note that A4 = 1, A4k+1 = A, A4k+2 = −I, A4+3 = -A for all k > 0 and determine the MacLaurin series expansion of cos(t) and sin(t)) To (ii) Write the integral formula for the solution X (t) in terms of X (0) = X₁ = and u. Yo (ii) Extract a separate formula for each component of X(t) = ((0)arrow_forwardThis is the fourth part of a four-part problem. If the given solutions ÿ₁ (t) = - [²2²], 2(0)-[¹7¹]. form a fundamental set (i.e., linearly independent set) of solutions for the initial value problem 21-² -21-2 y' = - [22 12t¹+2t 27 2t ¹-2t 2 [²], 2t | Ü‚ ÿ(5) — [34], t = t> 0, impose the given initial condition and find the unique solution to the initial value problem for t> 0. If the given solutions do not form a fundamental set, enter NONE in all of the answer blanks y(t) = (arrow_forwardSolve this.arrow_forward
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