Modified Mastering Physics with Pearson eText -- Combo Access -- for Physics for Scientist and Engineers (18 week)
5th Edition
ISBN: 9780137504299
Author: Douglas C. Giancoli
Publisher: Pearson Education (US)
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Modified Mastering Physics with Pearson eText -- Combo Access -- for Physics for Scientist and Engineers (18 week)
Ch. 8.2 - By how much does the potential energy change when...Ch. 8.4 - In Example 83, what is the rock's speed just...Ch. 8.4 - Two balls are released from the same height above...Ch. 8 - List some everyday forces that are not...Ch. 8 - You lift a heavy book from a table to a high...Ch. 8 - Analyze the motion of a simple swinging pendulum...Ch. 8 - Prob. 4QCh. 8 - A coil spring of mass m rests upright on a table....Ch. 8 - Experienced hikers prefer to step over a fallen...Ch. 8 - (a) Where does the kinetic energy come from when a...
Ch. 8 - Can the total mechanical energy E=K+Uever be...Ch. 8 - Describe the energy transformations when a child...Ch. 8 - Prob. 10QCh. 8 - Recall from Chapter 4, Example 414, that you can...Ch. 8 - Two identical arrows, one with twice the speed of...Ch. 8 - In Mg. 825, water balloons are tossed from the...Ch. 8 - Suppose that you wish to launch a rocket from the...Ch. 8 - Suppose you lift a suitcase from the floor to a...Ch. 8 - Repeat Question 23 for the power needed instead of...Ch. 8 - Why is it easier to climb a mountain via a zigzag...Ch. 8 - Prob. 18QCh. 8 - Prob. 19QCh. 8 - (a) Describe in detail the velocity changes of a...Ch. 8 - Prob. 1MCQCh. 8 - Prob. 2MCQCh. 8 - Prob. 3MCQCh. 8 - Prob. 4MCQCh. 8 - Prob. 5MCQCh. 8 - Prob. 6MCQCh. 8 - Prob. 7MCQCh. 8 - Prob. 8MCQCh. 8 - Prob. 9MCQCh. 8 - Prob. 10MCQCh. 8 - Prob. 11MCQCh. 8 - Prob. 12MCQCh. 8 - Prob. 13MCQCh. 8 - Prob. 1PCh. 8 - Prob. 2PCh. 8 - Prob. 3PCh. 8 - Prob. 4PCh. 8 - Prob. 5PCh. 8 - Prob. 6PCh. 8 - (II) A particle is constrained to move in one...Ch. 8 - (II) If U=3x2+2xy+4y2z, what is the force, F?Ch. 8 - Prob. 9PCh. 8 - Prob. 10PCh. 8 - Prob. 11PCh. 8 - (I) Jane, looking for Tarzan, is running at top...Ch. 8 - Prob. 13PCh. 8 - Prob. 14PCh. 8 - Prob. 15PCh. 8 - Prob. 16PCh. 8 - Prob. 17PCh. 8 - Prob. 18PCh. 8 - Prob. 19PCh. 8 - (II) A roller-coaster car shown in Fig. 832 is...Ch. 8 - (II) When a mass m sits at rest on a spring, the...Ch. 8 - Prob. 22PCh. 8 - Prob. 23PCh. 8 - Prob. 24PCh. 8 - Prob. 25PCh. 8 - (III) A skier of mass m starts from rest at the...Ch. 8 - Prob. 27PCh. 8 - Prob. 28PCh. 8 - (II) A ski starts from rest and slides down a 28...Ch. 8 - Prob. 30PCh. 8 - Prob. 31PCh. 8 - Prob. 32PCh. 8 - Prob. 33PCh. 8 - Prob. 34PCh. 8 - Prob. 35PCh. 8 - Prob. 36PCh. 8 - Prob. 37PCh. 8 - (III) A spring (k = 75 N/m) has an equilibrium...Ch. 8 - Prob. 39PCh. 8 - Prob. 40PCh. 8 - Prob. 41PCh. 8 - (I) For a satellite of mass mS in a circular orbit...Ch. 8 - (II) Show that Eq. 816 for gravitational potential...Ch. 8 - (II) Determine the escape velocity from the Sun...Ch. 8 - Prob. 45PCh. 8 - Prob. 46PCh. 8 - (II) Take into account the Earths rotational speed...Ch. 8 - (II) (a) Determine a formula for the maximum...Ch. 8 - Prob. 49PCh. 8 - Prob. 50PCh. 8 - (II) How much work would be required to move a...Ch. 8 - (II) A sphere of radius r1 has a concentric...Ch. 8 - (II) (a) Show that the total mechanical energy of...Ch. 8 - Prob. 54PCh. 8 - Prob. 55PCh. 8 - Prob. 56PCh. 8 - (I) An 85-kg football player traveling 5.0 m/s is...Ch. 8 - (I) If a car generates 18 hp when traveling at a...Ch. 8 - Prob. 59PCh. 8 - Prob. 60PCh. 8 - Prob. 61PCh. 8 - Prob. 62PCh. 8 - Prob. 63PCh. 8 - Prob. 64PCh. 8 - Prob. 65PCh. 8 - Prob. 66PCh. 8 - Prob. 67PCh. 8 - Prob. 68PCh. 8 - Prob. 69PCh. 8 - (III) A bicyclist coasts clown a 6.0 hill at a...Ch. 8 - Draw a potential energy diagram, U vs. x, and...Ch. 8 - Prob. 72PCh. 8 - Prob. 73PCh. 8 - (III) The potential energy of the two atoms in a...Ch. 8 - (III) The binding energy of a two-particle system...Ch. 8 - Prob. 78GPCh. 8 - Prob. 79GPCh. 8 - Prob. 80GPCh. 8 - Prob. 81GPCh. 8 - A ball is attached to a horizontal cord of length ...Ch. 8 - Show the h must be greater than 0.60 if the ball...Ch. 8 - Prob. 84GPCh. 8 - Prob. 85GPCh. 8 - Prob. 86GPCh. 8 - Prob. 87GPCh. 8 - Prob. 88GPCh. 8 - The small mass m sliding without friction along...Ch. 8 - Some electric power companies use water to store...Ch. 8 - A film of Jesse Owenss famous long jump (Fig. 849)...Ch. 8 - The nuclear force between two neutrons in a...Ch. 8 - Prob. 93GPCh. 8 - A fire hose for use in urban areas must be able to...Ch. 8 - Prob. 95GPCh. 8 - (II) (a) Suppose we have three masses, m1, m2, and...Ch. 8 - Prob. 97GPCh. 8 - Prob. 98GPCh. 8 - Prob. 99GPCh. 8 - Suppose the gravitational potential energy of an...Ch. 8 - A particle of mass m moves under the influence of...Ch. 8 - Prob. 102GPCh. 8 - Prob. 103GPCh. 8 - Prob. 104GP
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- A particle moves in the xy plane (Fig. P9.30) from the origin to a point having coordinates x = 7.00 m and y = 4.00 m under the influence of a force given by F=3y2+x. a. What is the work done on the particle by the force F if it moves along path 1 (shown in red)? b. What is the work done on the particle by the force F if it moves along path 2 (shown in blue)? c. What is the work done on the particle by the force F if it moves along path 3 (shown in green)? d. Is the force F conservative or nonconservative? Explain. FIGURE P9.30 In each case, the work is found using the integral of Fdr along the path (Equation 9.21). W=rtrfFdr=rtrf(Fxdx+Fydy+Fzdz) (a) The work done along path 1, we first need to integrate along dr=dxi from (0,0) to (7,0) and then along dr=dyj from (7,0) to (7,4): W1=x=0;y=0x=7;y=0(3y2i+xj)(dxi)+x=7;y=0x=7;y=4(3y2i+xj)(dyj) Performing the dot products, we get W1=x=0;y=0x=7;y=03y2dx+x=7;y=0x=7;y=4xdy Along the first part of this path, y = 0 therefore the first integral equals zero. For the second integral, x is constant and can be pulled out of the integral, and we can evaluate dy. W1=0+x=7;y=0x=7;y=4xdy=xy|x=7;y=0x=7;y=4=28J (b) The work done along path 2 is along dr=dyj from (0,0) to (0,4) and then along dr=dxi from (0,4) to (7,4): W2=x=0;y=0x=0;y=4(3y2i+xj)(dyj)+x=0;y=4x=7;y=4(3y2i+xj)(dyi) Performing the dot product, we get: W2=x=0;y=0x=0;y=4xdy+x=0;y=4x=7;y=43y2dx Along the first part of this path, x = 0. Therefore, the first integral equals zero. For the second integral, y is constant and can be pulled out of the integral, and we can evaluate dx. W2=0+3y2x|x=0;y=4x=7;y=4=336J (c) To find the work along the third path, we first write the expression for the work integral. W=rtrfFdr=rtrf(Fxdx+Fydy+Fzdz)W=rtrf(3y2dx+xdy)(1) At first glance, this appears quite simple, but we cant integrate xdy=xy like we might have above because the value of x changes as we vary y (i.e., x is a function of y.) [In parts (a) and (b), on a straight horizontal or vertical line, only x or y changes]. One approach is to parameterize both x and y as a function of another variable, say t, and write each integral in terms of only x or y. Constraining dr to be along the desired line, we can relate dx and dy: tan=dydxdy=tandxanddx=dytan(2) Now, use equation (2) in (1) to express each integral in terms of only one variable. W=x=0;y=0x=7;y=43y2dx+x=0;y=0x=7;y=4xdyW=y=0y=43y2dytan+x=0x=7xtandx We can determine the tangent of the angle, which is constant (the angle is the angle of the line with respect to the horizontal). tan=4.007.00=0.570 Insert the value of the tangent and solve the integrals. W=30.570y33|y=0y=4+0.570x22|x=0x=7W=112+14=126J (d) Since the work done is not path-independent, this is non-conservative force. Figure P9.30ANSarrow_forwardWhat average power is generated by a 70.0-kg mountain climber who climbs a summit of height 325 m in 95.0 min? (a) 39.1 W (b) 54.6 W (c) 25.5 W (d) 67.0 W (e) 88.4 Warrow_forwardA block of mass m = 2.50 kg is pushed a distance d = 2.20 m along a frictionless, horizontal table by a constant applied force of magnitude F = 16.0 N directed at an angle = 25.0 below the horizontal as shown in Figure P6.3. Determine the work done on the block by (a) the applied force, (b) the normal force exerted by the table, (c) the gravitational force, and (d) the net force on the block. Figure P6.3arrow_forward
- A nonconstant force is exerted on a particle as it moves in the positive direction along the x axis. Figure P9.26 shows a graph of this force Fx versus the particles position x. Find the work done by this force on the particle as the particle moves as follows. a. From xi = 0 to xf = 10.0 m b. From xi = 10.0 to xf = 20.0 m c. From xi = 0 to xf = 20.0 m FIGURE P9.26 Problems 26 and 27.arrow_forwardA 4.00-kg particle moves from the origin to position , having coordinates x = 5.00 m and y = 5.00 m (Fig. P7.31). One force on the particle is the gravitational force acting in the negative y direction. Using Equation 7.3, calculate the work done by the gravitational force on the particle as it goes from O to along (a) the purple path, (b) the red path, and (c) the blue path, (d) Your results should all be identical. Why? Figure P7.31arrow_forwardAn object of mass m = 5.8 kg moves under the influence of one force. That force causes the object to move along a path given by x = 6.0 + 5.0t + 2.0t2, where x is in meters and t is in seconds. Calculate the work done by the force on the object from t = 2.0 s to t = 7.0 s.arrow_forward
- (a) Can the kinetic energy of a system be negative? (b) Can the gravitational potential energy of a system be negative? Explain.arrow_forwardA particle is subject to a force Fx that varies with position as shown in Figure P7.9. Find the work done by the force on the particle as it moves (a) from x = 0 to x = 5.00 m, (b) from x = 5.00 m to x = 10.0 m, and (c) from x = 10.0 m to x = 15.0 m. (d) What is the total work done by the force over the distance x = 0 to x = 15.0 m?arrow_forwardA shopper pushes a grocery cart 20.0 m at constant speed on level ground, against a 35.0 N frictional force. He pushes in a direction 25.0° below the horizontal. (a) What is the work done on the cart by friction? (b) What is the work done on the cart by the gravitational force? (c) What is the work done on the cart by the shopper? (d) Find the force the shopper exerts, using energy considerations. (e) What is the total work done on the cart?arrow_forward
- A small block of mass m = 200 g is released from rest at point along the horizontal diameter on the inside of a frictionless, hemispherical bowl of radius R = 30.0 cm (Fig. P8.43). Calculate (a) the gravitational potential energy of the block-Earth system when the block is at point relative to point . (b) the kinetic energy of the block at point . (c) its speed at point B, and (d) its kinetic energy and the potential energy when the block is at point . Figure P8.43 Problems 43 and 44.arrow_forward(a) A force F=(4xi+3yj), where F is in newtons and x and y are in meters, acts on an object as the object moves in the x direction from the origin to x = 5.00 m. Find the work W=Fdr done by the force on the object. (b) What If? Find the work W=Fdr done by the force on the object if it moves from the origin to (5.00 m, 5.00 m) along a straightline path making an angle of 45.0 with the positive x axis. Is the work done by this force dependent on the path taken between the initial and final points?arrow_forwardA particle moves along the xaxis from x = 12.8 m to x = 23.7 m under the influence of a force F=375x3+3.75x where F is in newtons and x is in meters. Using numerical integration, determine the work done by this force on the particle during this displacement. Your result should he accurate to within 2%.arrow_forward
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