Introduction to Electrodynamics
4th Edition
ISBN: 9781108420419
Author: David J. Griffiths
Publisher: Cambridge University Press
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Assume MKS units...
Let Q be an open subset of R³. Let B: :Q - R³ be a continuous vector
.field, representing a magnetic field in 3-D space.
7
Let P be a particle with charge q E R and mass m > 0. If p is at position
(x. y, z) in Q and R³ is the velocity of p, at time t, then p feels a
force 7(7,7) given by
-
7(7,J) := q V × B (7) .
Suppose that p moves along a curve C as time t varies from a to b, and that
p has position vector (t) and instantaneous velocity (t) at time t.
ř
(1) Explain why the two vectors 7'(t) × È(7(t)) and 7'(t) are perpen-
dicular at every time t = [a, b].
(2) Using Part (1), calculate W := the work done on the particle p by the
force as p moves from D = 7(a) to E = √ (b) along C.
F
(3) Prove that
((t)||²)=27' (t) • F(t),
at each time t.
(4) Using Parts (2) and (3), and Newton's Second Law, prove that if the
magnetic force - ₹(7,7) is the total force on p at every time t, then p
moves along C at a constant speed.
dt
A very long, straight current-carrying wire is bent at the middle two different ways, sothat it takes the shapes depicted in figures a) and b). Find the direction and magnitude of themagnetic field in both cases at the center C of the semicircle (of radius R = 10 cm), if the currentflowing in the wire is I = 2 A.
A charge q = 54 C is located at (9, 8) and we want to find the electric field at pint p (3, 5). Find the source to point vector.
Use the following constants if necessary. Coulomb constant, k = 8.987 × 10° N · m² /C² . Vacuum permitivity, €o = 8.854 × 10-12 F/m. Magnetic
Permeability of vacuum, µo = 12.566370614356 ×x 10-7 H/m. Magnitude of the Charge of one electron, e = -1.60217662 × 10¬19 C. Mass of one
9.10938356 x 10-31 kg. Unless specified otherwise, each symbol carries their usual meaning. For example, µC means micro coulomb
electron, me
x component of the vector
Give your answer up to at least three significance digits.
y component of the vector
Give your answer up to at least three significance digits.
Knowledge Booster
Similar questions
- 5.34 PQ Explain the differences between the Eulerian and Lagrangian descriptions of a flow field.arrow_forwardProblem 7.21 Imagine a uniform magnetic field, pointing in the z direction and filling all space (B = Bo 2). A positive charge is at rest, at the origin. Now somebody turns off the magnetic field, thereby inducing an electric field. In what direction does the charge move? 16arrow_forward2.1 Use the Biot-Savart law to obtain an expression for the magnetic field at a point B(r) in terms of the integral of the local current density j(r'). Hence show that the divergence of B is zero.arrow_forward
- Consider a particle of charge 8.8 that is traveling with speed 90 m/s in a direction that is 19 degrees south of east. The particle is moving in a magnetic field of strength 1 T that points in a direction 30 degrees south of west. Calculate the magnitude of the force on the particle, in N. (Please answer to the fourth decimal place - i.e 14.3225)arrow_forward5.34 In Fig. P5.34, the plane defined by x - y = 1 separates medium 1 of permeability µi from medium 2 of permeability u2. If no surface current exists on the boundary and B = 82 + ŷ3 (T), find B2 and then evaluate your result for 41 = 5µ2. Hint: Start by deriving the equation for the unit vector normal to the given plane. Plane x- y = 1S Medium 1 (1, 0) Medium 2 (0, -1) Figure P5.34 Magnetic media separated by the plane.x-y = 1 (Problem 5.34).arrow_forwardUse the Biot-Savart law to calculate the magnetic field B of a ribbon with finite width (w). Suppose it's at a random point P (generalized 3D position) Hint: you can find the vector potential A first to do the integral, then find B Magnetic field of a current-carrying ribbon. (B-field lines of an individual strip) dlarrow_forward
- 1.7.5 Verify the vector identity V x (A x B) = (BV)A- (AV)B-B(V A) +A(V B). Describe in words what causes the last two terms to appear in the identity beyond the BAC-CAB rule. If symbolic software is available, test the Cartesian components for a typical case, such as A = L, B =arrow_forward9.3. A system of two conductors has a cross section given by the intersection of two circles of radius b with centers separated by 2a as shown in figure below. The conducting portion is shown hatched, the non-hatched lens-shaped region being a vacuum. The conductor on the left carries a uniform current density, J1, coming out of the page, and the conductor on the right carries a uniform current density, −J 12, going into the page. Assume that the magnetic permeability of the conductor is the same as that of the vacuum. Find the magnetic field at all points in the vacuum enclosed between the two conductors. 2aarrow_forwardExample 7.7. A uniform magnetic field B(1), pointing straight up, fills the shaded circular region of Fig. 7.25. If B is changing with time, what is the in- duced electric field? Solution E points in the circumferential direction, just like the magnetic field inside a long straight wire carrying a uniform current density. Draw an Amperian loop of radius s, and apply Faraday's law: do E-d1 = E(27s) = (s²B(1)) =-7S 2 dB di dt Therefore s dB E 2 dr If B is increasing, E runs clockwise, as viewed from above. 13 Magnetostatics holds only for time-independent currents, but there is no such restriction on 3B/ar. Chapter 7 Electrodynamics B(1) E Amperian loop FIGURE 7.25 dt Rotation direction dl λ FIGURE 7.26arrow_forward
- 1 Normal 1 No Spaci... Heading 1 Heading 2 Title Subtitle Subtle Paragraph Styles A vector Magnetic potential given by relation A=5p()k in cylindrical coordinates (u,, uo,k). find the electric field at the Cartesian coordinates (i, j,k)arrow_forwardShow that (2.6) reduces to (a) (2.7 ) for a circular current loop and (b) (2.8) fora square current loop.arrow_forward(a) Show that the period of the circular orbit of acharged particle moving perpendicularly to a uniformmagnetic field is T=2*pi*m/ (QB) . (b) What is thefrequency? (c) What is the angular velocity? Note that these results are independent of the velocity andradius of the orbit and, hence, of the energy of theparticle. (Figure 22.64.)arrow_forward
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