Chapter 6, Problem 6.106P

Solve it fast and correctly please.

The figure shows data for a portion of the ducting in a ventilation system operating at steady state. The ducts are well insulated and the pressure is very nearly 1 atm throughout. The volumetric flow rate entering at state 2 is AV2 = 2800 ft³/min. Assume the ideal gas model for air with c, = 0.24 Btu/lb•°R and ignore kinetic and potential energy effects. 1 (AV)1 = 5000 ft /min Air, Co = 0.24 Btu/lb°R T, = 80°F p=1 atm 3 V3 = 400 ft/min T3 = ? 2 (AV)2 Tz = 40°F -Insulation ft/min Determine the temperature of the air at the exit, in °F, and the rate of entropy production within the ducts, in Btu/min-°R.

Steam at 44 bar and a dryness fraction, x = 0.9 is throttled to a pressure of 12 bar. Calculate thedifference in power output in kilowatts between the following two expansion processes:a) Steam at the initial pressure of 44 bar and x = 0.9 at State 1 is expanded in a turbine to State 3 at 0.12 bar.b) Steam at the reduced pressure of 12 bar after throttling at State 2 is expanded in another turbine to State 4 at the same exhaust pressure of 0.12 bar.The mass flow rate of steam is 8 kg/sec in both cases and the expansion in both turbines can be assumed to be reversible and adiabatic. Sketch both expansion processes on the same T-s diagram using the respective initial and final state points as described above.Explain the reason for the difference in power output.Calculate the mass flow rate of steam for the turbine operating at the throttled/reduced pressure to generate the same output as the turbine operating at the pressure before throttling.NOTE: You are required to number the state…