College Physics
1st Edition
ISBN: 9781938168000
Author: Paul Peter Urone, Roger Hinrichs
Publisher: OpenStax College
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Chapter 6, Problem 43PE
A geosynchronous Earth satellite is one that has an orbital period of precisely 1 day. Such orbits are useful for communication and weather observation because the satellite remains above the same point on Earth (provided it orbits in the equatorial plane in the same direction as Earth's rotation). Calculate the radius of such an orbit based on the data for the moon in Table 6.2
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A 3000-kg satellite orbits the Earth in a circular orbit 11797 km above the Earth's
surface (Earth radius = 6380 km, Earth Mass = 5.97x1024 kg).
What is the gravitational force (in newtons, N) between the satellite and the Earth?
Hint: The radius of the Earth + the height of the orbit = the center-to-center distance needed
for the equation. You also need the universal gravitational constant (G), which is not 9.81
m/s2. Be careful.
Gmim2
F
A geosynchronous Earth satellite is one that has an orbital period of precisely 1 day. Such orbits are useful for communication and weather observation because the satellite remains above the same point on Earth (provided it orbits in the equatorial plane in the same direction as Earth's rotation). Calculate the radius (in km) of such an orbit based on the data for the moon in this table.
A geosynchronous Earth satellite is one that has an orbital period of precisely 1 day. Such orbits are useful for communication and weather observation because the satellite remains above the same point on Earth (provided it orbits in the equatorial plane in the same direction as Earth’s rotation). Calculate the radius of such an orbit based on the data for the moon in Table.
Chapter 6 Solutions
College Physics
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