Advanced Placement Calculus 2016 Graphical Numerical Algebraic Fifth Edition Student Edition
5th Edition
ISBN: 9780133311617
Author: Prentice Hall
Publisher: Prentice Hall
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A wind is blowing giving the projectile the acceleration of 9m/s2 in the positive direction of the y-axis. Assuming that the gravity is 9.5m/s2, write the
acceleration of the projectile at any time t.
a(t)=
BSP;+
OOP.
Suppose a stone is thrown vertically upward with an initial velocity of 48 ft/s from a bridge 64 ft
above a river. By Newton's laws of motion, the position of the stone (measured as the height above
the river) after t seconds is s(t) = -16t² + 48t + 64, where s = 0 is the level of the river.
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a). Find the velocity and acceleration functions.
b). What is the highest point above the river reached by the stone?
c). With what velocity will the stone strike the river?
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- The kinetic energy E of an object varies jointly with the object’s mass m and the square of the object’s velocity v . An object with a mass of 50 kilograms traveling at 16 meters per second has a kinetic energy of 6400 joules. What is the kinetic energy of an object with a mass of 70 kilograms traveling at 20 meters per second?arrow_forwardTransient Orifice Flow: Water is discharged from a reservoir through a long pipe as shown. By neglecting the change in the level of the reservoir, the transient velocity of the water flowing from the pipe, vt), can be expressed as: - Reservoir v(t) V2gh = tanh V2gh) Pipe Where h is the height of the fluid in the 7- reservoir, L is the length of the pipe, g is the acceleration due to gravity, and t is the time elapsed from the beginning of the flow Transient Orifice Flow: Determine the helght of the fluid in the reservoir at time, t= 2.5 seconds, given that the velocity at the outfall, vt) = 3 m/s, the acceleration due to gravity, g = 9.81 m/s? and the length of the pipe to outfall, L= 1.5 meters. Reservoir v(t) V2gh = tanh 2L 2gh water Pipe Hint: Transform the equation to a function of form: fih) = 0 Solve MANUALLY using BISECTION AND REGULA-FALSI METHODS, starting at xn = 0.1, Kg =1, E = 0.001 and If(*new)l < Earrow_forwardA4) The position of a hummingbird flying along a straight line in t seconds is given by S(t) = 2t - 20t meters. [ 1 mark ] (a) Determine the velocity of the bird at t = 3 sec. [0.25 mark] (b) Determine the acceleration of the bird at t = 3 sec. [0.25 mark] (c) Determine the acceleration of the bird when the velocity equals 0. [0.5 mark]arrow_forward
- Need only a handwritten solution only (not a typed one).arrow_forward1.) Let s(t)= tlnt-t be the displacement of a particle (in feet) from the origin after t seconds. a.) Find the velocity of the particle at 5 seconds. (Show all your work and include units) b.) Find the acceleration of the particle after 5 seconds. (Show all your work and include units)arrow_forwardCan you please help explain this question on how to get answer?arrow_forward
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