You are sitting next to a person who has twice as much weight. Are you gravitationally attracted to them? If so, is it twice as much as their attraction to you? If not, why not?

The Oort Cloud extends out to (possibly) one light-year from the sun.  Objects in the Oort Cloud are still gravitationally bound to the sun.  Suppose one such iceball orbits the sun in a circle.  I'm going to alter some numbers, such as the mass of the sun and even G.  The gravitational force is directed toward the sun and has the following magnitude: Calculate the force on the object if these are the numbers: G = 6.1*10-11 N*m2/kg2 M = 2.7*1030 kg m = 1.5*108 kg r = 19*1015 m Calculate your answer in microNewtons (10-6 N).

An object with mass is thought of as being surrounded by a gravitational field. The concept of the gravitational field becomes useful in explaining

We will use differential equations to model the orbits and locations of Earth, Mars, and the spacecraft using Newton’s two laws mentioned above. Newton’s second law of motion in vector form is: F^→=ma^→ (1) where F^→ is the force vector in N (Newtons), and a^→ is the acceleration vector in m/s^2,and m is the mass in kg. Newton’s law of gravitation in vector form is: F^→=GMm/lr^→l*r^→/lr^→l where G=6.67x10^-11 m^3/s^2*kg is the universal gravitational constant, M is the mass of the larger object (the Sun), and is 2x10^30 kg, and m is the mass the smaller one (the planets or the spacecraft). The vector r^→ is the vector connecting the Sun to the orbiting objects. Step one ) The motion force in Equation(1), and the gravitational force in Equation(2) are equal. Equate the right hand sides of equations (1) and (2), and cancel the common factor on the left and right sides. Answer: f^→=ma^→        f=Gmm/lr^→l^2         a^→=Gmm/lr^→l^2 x r^→/lr^→l        r^→=r^→/lr^→l * Gmm Could you please…

It has been speculated that gravity does not truly exist as a force in and of itself, but is instead a manifestation of the electrostatic force, which is the force responsible for the repulsion of like-charges and the attraction of opposite charges. Is this a credible theory? Why or why not? What experiment could a person conduct to test this theory?

A 4.00 x 10^8 kg mass and 5.00 x 10^8 kg mass are separated by a distance of 2.0 km. What is the gravitational force of attraction between the masses?

Gravitational forces are different from electrostatic forces because gravitational forces are: O Repulsive, only O Attractive, only O Neither attractive nor repulsive Both attractive and repulsive

Why don't you feel a gravitational force from the text book you're reading?

Why is the concept of Gravitational fields useful in Physics?

Field g on Different Planets 1 3. m m m,r m,2r 2 > 受,2r Four planets have relative masses and radii as shown above. The gravitational field g is smallest on the surface of which planet? 1 2 4 4. 2.