Explanation Given info: The length of the wire ( L ) = 12 m . Calculation : The length of the wire is bent into a square and a circle. Assuming the length of the wire bent into two pieces of length x and L − x .so we take, Length of a square = x Length of a circle = L − x L − x = 12 − x Side of the squre = x 4 Area of the square A s = ( x 4 ) 2 Radius of the circle = 12 − x 2 π Area of the circle A c = π ( 12 − x 2 π ) 2 Total area, A T = ( x 4 ) 2 + π ( 12 − x 2 π ) 2 = x 16 2 + π ( 12 − x ) 4 π 2 2 = x 16 2 + 144 + x 2 − 24 x 4 π Then we take d A T d x

4th Edition

ISBN: 9781319323394

Author: Rogawski

Publisher: MAC HIGHER

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Chapter 4.6, Problem 7E

To determine

Find the sum of their areas of a square and a circle.

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Chapter 4.6, Problem 6E

Chapter 4.6, Problem 8E

Chapter 4 Solutions

CALCULUS W/SAPLING ACCESS >IC<

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Find the sum of their areas of a square and a circle.

Solution Summary: The author explains how the length of the wire is bent into two pieces of length x and L-x.

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Find the sum of their areas of a square and a circle.

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Chapter 4 Solutions