105. DISCUSS: Disguised Equations Each of these equations can be transformed into an equation of linear or quadratic type by applying the hint. Solve each equation. (a) (x – 1)log(-=1) = 100(x – 1) [Hint: Take log of each side.] (b) log, x + log, x + logs x = 11 [Hint: Change all logs to base 2.] (c) 4' – 2** = 3 [Hint: Write as a quadratic in 2".]

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.6: Exponential And Logarithmic Equations
Problem 28E
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DISCUSS: Disguised Equations Each of these equations
can be transformed into an equation of linear or quadratic
type by applying the hint. Solve each equation.
(a) 1x  12
log1x12  1001x  12
[Hint: Take log of each side.]
(b) log2 x  log4 x  log8 x  11
[Hint: Change all logs to base 2.]
(c) 4x  2x1  3
[Hint: Write as a quadratic in 2x
.]

105. DISCUSS: Disguised Equations Each of these equations
can be transformed into an equation of linear or quadratic
type by applying the hint. Solve each equation.
(a) (x – 1)log(-=1) = 100(x – 1)
[Hint: Take log of each side.]
(b) log, x + log, x + logs x = 11
[Hint: Change all logs to base 2.]
(c) 4' – 2** = 3
[Hint: Write as a quadratic in 2".]
Transcribed Image Text:105. DISCUSS: Disguised Equations Each of these equations can be transformed into an equation of linear or quadratic type by applying the hint. Solve each equation. (a) (x – 1)log(-=1) = 100(x – 1) [Hint: Take log of each side.] (b) log, x + log, x + logs x = 11 [Hint: Change all logs to base 2.] (c) 4' – 2** = 3 [Hint: Write as a quadratic in 2".]
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