Chapter 4, Problem 82P

The force F=5i+12j+4k lb is applied to the handle of the door. Determine the orthogonal component of F that is perpendicular to the plane of the door.

Determine the moment of the force F about point A in terms of F and d. Use (a) the scalar method; and (b) the vector method.

When the three forces are replaced by an equivalent force-couple system with the force at point O, the couple vector CR is directed parallel to the x-axis. Determine F and the resultant force-couple system.

The two forces are applied to the end of the boom OA. Determine the force F so that the resultant of the two forces lies in the yz-plane.

To move the oil drum, the resultant of the three forces shown must have a magnitude of 500 N. Determine the magnitude and direction of the smallest force F that would cause the drum to move.

The moment of the force F=50i100j70klb about point O is MO=400i+410j300klbft. Determine the coordinates of the point where the line of action of F intersects the xz-plane.

The force R is the resultant of P and 0. Determine Q and the angle .

The pole OB is subjected to the 6004b force at B. Determine (a) the rectangular components of the force; and (b) the angles between the force vector and the coordinate axes.

The force-couple system consists of the force R=250i+360j400kN and the couple-vector CR=1200i+750j+560kNm. Determine the equivalent wrench and find the coordinates of the point where the axis of the wrench crosses the xy-plane.