21ST CENTURY ASTRONOMY >CUSTOM<
6th Edition
ISBN: 9781324027836
Author: Kay
Publisher: NORTON
expand_more
expand_more
format_list_bulleted
Question
Chapter 4, Problem 11QP
To determine
The change in the tides on Earth, if the Moon is
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
Currently, the moon goes around the earth once every 27.3 days. If the moon could be brought into a new circular orbit with a smaller radius, its orbital period would beA. More than 27.3 days.B. 27.3 days.C. Less than 27.3 days.
Each year, the radius of the moon’s orbit increases by about 3.8 cm. How does this change affect the length of a month?A. A month gets longer.B. A month gets shorter.C. The length of a month stays the same.
8. The mean distance of Earth from the Sun is 149.6 x 10° km and the mean distance of
Mercury from the Sun is 57.9 x 10° km. The period of Earth's revolutions is 1 year,
what is the period of Mercury's revolution?
a. 0.24 year on Earth
b. 0.42 year on Earth
C. 1.13 year on Earth
d. 1.31 year on Earth
9. The planet Delta has 2 times the gravitational field strength and 3 times the radius of
Earth. How does the mass of the planet Delta compare with the mass of Earth?
Chapter 4 Solutions
21ST CENTURY ASTRONOMY >CUSTOM<
Ch. 4.1 - Prob. 4.1ACYUCh. 4.1 - Prob. 4.1BCYUCh. 4.2 - Prob. 4.2CYUCh. 4.3 - Prob. 4.3CYUCh. 4.4 - Prob. 4.4CYUCh. 4 - Prob. 1QPCh. 4 - Prob. 2QPCh. 4 - Prob. 3QPCh. 4 - Prob. 4QPCh. 4 - Prob. 5QP
Ch. 4 - Prob. 6QPCh. 4 - Prob. 7QPCh. 4 - Prob. 8QPCh. 4 - Prob. 9QPCh. 4 - Prob. 10QPCh. 4 - Prob. 11QPCh. 4 - Prob. 12QPCh. 4 - Prob. 13QPCh. 4 - Prob. 14QPCh. 4 - Prob. 15QPCh. 4 - Prob. 16QPCh. 4 - Prob. 17QPCh. 4 - Prob. 18QPCh. 4 - Prob. 19QPCh. 4 - Prob. 20QPCh. 4 - Prob. 21QPCh. 4 - Prob. 22QPCh. 4 - Prob. 23QPCh. 4 - Prob. 24QPCh. 4 - Prob. 25QPCh. 4 - Prob. 26QPCh. 4 - Prob. 27QPCh. 4 - Prob. 28QPCh. 4 - Prob. 29QPCh. 4 - Prob. 30QPCh. 4 - Prob. 31QPCh. 4 - Prob. 32QPCh. 4 - Prob. 33QPCh. 4 - Prob. 34QPCh. 4 - Prob. 35QPCh. 4 - Prob. 36QPCh. 4 - Prob. 37QPCh. 4 - Prob. 38QPCh. 4 - Prob. 39QPCh. 4 - Prob. 40QPCh. 4 - Prob. 41QPCh. 4 - Prob. 42QPCh. 4 - Prob. 43QPCh. 4 - Prob. 44QPCh. 4 - Prob. 45QP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Which of the following is a measurable effect of the tidal interactions between the Earth and the moon? choose 1 of the following: a. The moon is constantly getting closer to the Earth, and will one day collide with our planet. b. The rotation rate of the Earth is gradually slowing down. c. The rotation rate of the moon is gradually speeding up. d. The moon pulls more strongly on the far side of the Earth than it does on the near side.arrow_forwardAccording to Lunar Laser Ranging experiments the average distance LM from the Earth to the Moon is approximately 3.85 × 10° km. The Moon orbits the Earth and completes one revolution in approximately 27.5 days (a sidereal month). How can the mass of the Earth be calculated using the information above? Select the correct statements. Select one or more: O a. Use Newton's third law. O b. Use Newton's first law. c. Use Coulombs law. O d. Use Newton's second law.arrow_forwardThe friction created when tidal forces move ocean waters over the seabeds a. causes the lunar phases. b. slows the rotation of Earth, gradually making the days longer c. forces the moon to approach Earth. d. has no effect on Earth. e. has no effect on the moon.arrow_forward
- 1. Mars takes 1.88 years to complete one orbit around the sun. What is its average distance from the sun?arrow_forward6. Determine what the period of revolution of the Earth would be if its distance from the Sun were 4 AU rather than 1 AU. Assume that the mass of the Sun remains the same.arrow_forward1. The reason that there are two daily tides on Earth is that one occurs when the sun is overhead and the other when the Moon is overhead. True or False 2. Tides are approximately 24 hours apart. True or Falsearrow_forward
- 2. An unknown planet was accidentally discovered by NASA. It has a mean distance of 2.15 E11 meters from the sun. Assuming it has a mass of 6.02 E24 kg, how long (in Earth Years) will it take for the said planet to revolve around the sun?arrow_forwardThe rotation of the planets around the sun is governed by: A. The gravitational field of the sun. B. The gravity of the stars. C. The heat energy of the sun. D. The gravity of the other planets of the solar system. Kelper's second law relates between them: O A. The time period of rotation of the orbiting planet around the sun and the average distance of the planet to the sun. OB. The time period of rotation of the orbiting planet around the sun and the average distance of the planet to the earth. C. The time period of rotation of the orbiting planet around the sun and the average distance of the planet to the moon. OD. The time period of rotation of the orbiting planet around the earth and the average distance of the planet to the sun.arrow_forward1. The tides are present on earth because... A) the sun causes the earth to orbit B) the moon has a negligible gravitational effect on the earth except for in the oceans C) there is a different force of gravity acting on either side of the earth resulting from the moon D) tectonic plates shift as the earth rotates causing the water levels to vary.arrow_forward
- 7. What is the gravity constant in our planet? a. 10 m/s2 b. 2.3 m/s2 c. 1.0 m/s2 d. 9.8 m/s2arrow_forward6. A synchronous orbit is an orbit about a planet's equator that always remains above the same spot of the planet because the synchronous orbit matches the planet's rotational period. The pilot of the Mars spacecraft (which was named Cheetah 1 and had a 9556 kg mass) asked Tarzan to calculate the altitude of a synchronous orbit so they could remain over a particular geological feature on the Martian equator. Calculate the altitude above the Martian equator using the data above and Johannes Kepler's genius.arrow_forward25. The mean distance of Earth from the Sun is 149.6 x 10° km and the mean distance of Mercury from the Sun is 57.9 x 106 km. The period of Earth's revolutions is 1 year, what is the period of Mercury's revolution? a. 0.24 year on Earth b. 0.42 year on Earth C. 1.13 year on Earth d. 1.31 year on Eartharrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Classical Dynamics of Particles and SystemsPhysicsISBN:9780534408961Author:Stephen T. Thornton, Jerry B. MarionPublisher:Cengage LearningAn Introduction to Physical SciencePhysicsISBN:9781305079137Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar TorresPublisher:Cengage LearningHorizons: Exploring the Universe (MindTap Course ...PhysicsISBN:9781305960961Author:Michael A. Seeds, Dana BackmanPublisher:Cengage Learning
Classical Dynamics of Particles and Systems
Physics
ISBN:9780534408961
Author:Stephen T. Thornton, Jerry B. Marion
Publisher:Cengage Learning
An Introduction to Physical Science
Physics
ISBN:9781305079137
Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres
Publisher:Cengage Learning
Horizons: Exploring the Universe (MindTap Course ...
Physics
ISBN:9781305960961
Author:Michael A. Seeds, Dana Backman
Publisher:Cengage Learning
Components of a Vector (Part 1) | Unit Vectors | Don't Memorise; Author: Don't Memorise;https://www.youtube.com/watch?v=fwMUELxZ0Pw;License: Standard YouTube License, CC-BY
02 - Learn Unit Conversions, Metric System & Scientific Notation in Chemistry & Physics; Author: Math and Science;https://www.youtube.com/watch?v=W_SMypXo7tc;License: Standard Youtube License