Chapter 4, Problem 111P

The design specifications for the attachment at A for this beam depend on the magnitude and location of the applied loads. Represent the resultant of the three forces and couple by a single force R at A and a couple moment. Take: M 25 kN .m ;a = 30 ; x = 1.6.m 4 kN 2 m -1.5 m- -0.8 m 2 kN 3 kN

The equivalent resultant force acting on the beam is zero and the resultant couple moment is 7 kN⋅m clockwise. Determine the position a of the triangular load on the beam.

1. Determine the magnitude of the moment of the 200-N force about the x axis. Solve 0.3 m F= 200 N the problem using both a scalar and a 45 vector analysis. 120 60 0.25 m 2. The chain AB exerts a force of 20 lb on the 3 ft door at B. Determine the magnitude of the 2 ft moment of this force along the hinged axis x of the door. F= 20 lb B. 4 ft 3 ft 20°

Replace the loading by an equivalent resultant force and couple moment at point B.

To lift the table without tilting, the combined moment of the four parallel forces must be zero about the x-axis and the y-axis (O is the center of the table). Determine the magnitude of the force F and the distance d.

Determine the moment of the force F=40i8j+5kN about the y-axis.

The forces P and Q act on the handles of the wrench. If P = 321b and Q = 36 lb, determine the combined moment of the two forces about the z-axis.

(a) Replace the force F=2800i+1600j+3000klb acting at end A of the crank handle with a force R acting at O and a couple-vector CR. (b) Resolve R into the normal component P (normal to the cross section of the shaft) and the shear component V (in the plane of the cross section). (c) Resolve CR into the twisting component T and the bending component M.

Determine the moment of the force F about point A in terms of F and d. Use (a) the scalar method; and (b) the vector method.