An object is placed 12.0 cm to the left of a diverging lens of focal length 26.00 cm. A converging lens of focal length 12.0 cm is placed a distance d to the right of the diverging lens. Find the distance d so that the final image is infinitely far away to the right.

A 3 cm tall object is placed 16 cm from a converging lens with a focal length of 12 cm. A diverging lens with a focal length of 10 cm is placed 36 cm behind the converging lens. Both lenses have the same principal axis. Draw the ray diagram to graphically find the final image. Need only handwritten solution only (not typed one).

An object is located 50.0 m to the left a converging lens of focal length 15.0 cm. A diverging lens of focal length 4.20 cm is placed 10.0 cm to the right of the converging lens. Locate (final image position) and describe (real or virtual, upright or inverted, reduced or enlarged) the final image of the object formed by the two-lens system.

For safety reasons, you install a rear-window lens with a -0.299 m focal length in your van. Before putting the van in reverse, you look through the lens and see the image of a person who appears to be 0.339 m tall and 0.243 m behind the van. Determine the following. (a) actual distance of the person behind the van m (b) height of the person

The lens-maker’s equation for a lens with index n1 immersed in a medium with index n2 takes the form A thin diverging glass (index = 1.50) lens with R1 = −3.00 m and R2 = −6.00 m is surrounded by air. An arrow is placed 10.0 m to the left of the lens. (a) Determine the position of the image. Repeat part (a) with the arrow and lens immersed in (b) water (index = 1.33) (c) a medium with an index of refraction of 2.00. (d) How can a lens that is diverging in air be changed into a converging lens?

A system of two lenses forms an image of an arrow at x = x3 = 57.4 cm. The first lens is a diverging lens located at x = 0 and has a focal length of magnitude f₁ = 11.5 cm. The second lens is located at x = x₂ = 25.4 cm and has an unknown focal length. The tip of the object arrow is located at (x,y) = (xo, Yo) = (-36 cm, 20.6 cm). (x,y) 1) What is x₁, the x-coordinate of image of the arrow formed by the first lens? cm Submit 2) What is y₁, the y-coordinate of the image of the tip of the arrow formed by the first lens? cm Submit X₂ Real and Inverted Real and Upright Virtual and Inverted Virtual and Upright cm Submit (+) 3) What is f2, the focal length of the second lens. If the lens is a converging lens, f2 is positive. If the lens is a diverging lens, f2 is negative. cm Submit + 4) What is y3, the y-coordinate of the image of the tip of the arrow formed by the two lens system? (+ 5) The positions of the two lenses are now interchnaged (i.e., the second lens is moved to x = 0 and the…