College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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A patient has a near point of 45.0 cm and far point of 85.0 cm. (a) Can a single pair of glasses correct the patient’s vision? Explain the patient’s options. (b) Calculate the power lens needed to correct the near point so that the patient can see objects 25.0 cm away. Neglect the eye–lens distance. (c) Calculate the power lens needed to correct the patient’s far point, again neglecting the eye–lens distance.
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- Which of the following statements is true about an eye that is farsighted? Question 17 options: The image is in front of the retina, and this can be corrected by a converging lens. The image is in back of the retina, and this can be corrected by a converging lens.arrow_forwardWhat is the power ? of the eye when viewing an object 41.0 cm away? Assume the lens-to-retina distance is 2.00 cm , and express the answer in diopters. Power???arrow_forwardCreate a ray diagram for eyeglasses that contain a diverging lens. Assume you are looking at a 2 cm tall object that is 4 cm from the lens. The focal length is 3 cm. What type of vision are they used to correct? Give both names. How do they do this? Explain.arrow_forward
- A patient cannot clearly see any object that lies closer than 32.0 cm to her right eye. However, the patient wishes to see objects as close as 20.0 cm with that eye. The patient requests eyeglasses to address the problem. (a) Is the patient nearsighted or farsighted? nearsightedfarsighted (b) If the eyeglass lens lies 2.10 cm in front of the patient's eye, what is the minimum distance p (in cm) separating the lens from an object she wants to see? (Give your answer to at least three significant digits.) cm (c) The patient is unable to focus clearly on anything closer than 32.0 cm to her eye (this being the patient's near point). The image formed by the eyeglass lens must therefore be 32.0 cm from the eye. How far, then, (in cm) would the image lie from the lens? (Give your answer to at least three significant digits.) cm (d) The image lies on the same side of the lens as the original object. Is the image real or virtual, and is its position q positive or…arrow_forwardA very myopic woman has a far point of 23.8 cm. What power contact lens (in D, when on the eye) will correct her distant vision? (Take the lens-to-retina distance to be 2.00 cm.) -0.49 D -0.04 D -2.28 D -4.20 Darrow_forward
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