15.) Use Descartes Rule of signs to determine how many positive and how many negative real zeros the polynomial can have.  Then determine the possible total number of real zeros. P(x)= 3x3 - X2+2x - 8 a. 1 positive, 1 negative b. 1 negative c. 3 negative d. 0 or 2 positive e. 1 or 3 positive

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Q: 16. P(x) = zeros. 2x4 - x³ - 27x² + 16x - - 80; -4 and 4 are

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Q: 6. Use Descartes's Rule of Signs to determine the possible number of positive and negative real…

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Polynomials

Try substituting 1. You will get 6 and not 0. Try other real values also. What About -2? Let us check.