0 17 0 2 1 0 T1 3 1 0. B = 1 1 4 1 A = 0 0 1 3 0 0 1 1 0 0 0 4 1 1 1

Q: |1 2 3 0 1 1 1 (g) 0 0 1 3 100 2

A:

Q: О А. НО: р 0.1

A: p = 26/349 =0.07   population proportion = 0.1

Q: 1 1 1 1 1 0 0 0 1

A: First we write augmented matrix of given matrix and identity matrix  And try to convert given matrix…

Q: Y 3.0 0,00 FU.25 0.50 0.25 1.75 0.75 2.5 1.00 B. 25 2.0 2.75 1.5 3.25 L00 1.0 3.50 0.5 3.75 0.0 2.25…

A: We use central difference to approximate the derivative at point E in direction of E.

Q: 1 0 0 0 5 10 0 A = 7 -5 1 0 -5 -6 5 1 Then A-1 %3D

A:

Q: 1 3 P(X=x) 0.15| 0.20 0.15 0.50

A:

Q: 1 0 0 0 0 1 0 0 0 0 0 0 0 1 1 A = 1 1 13 0 0 1 0 5 B = 0 0 0 1 0 0 0 3 1 12 2 0 0 1 7 C = 0 0 0 0 1…

A:

Q: 3.1.13 1.25 1.5 1.75 2.25 f(x) 0.2 0.4 0.1 0.2 0.1 0.1 a. P(X > 2) b. РСХ 2.1) 2.

A: See the handwritten solution

Q: P(X) 0. 0.2 1 0.2 0.1 0.5 23

A: We know that, when we have a probability distribution, then to find the standard deviation, we have…

Q: 1. 5х2у" + 23ху' + 16.2у —D 0 2. х?у" + 0.7ху' — 0.1у %3D 0 3. х2у" — 0.7ху — 0.1у %3D0 |

A: Given

Q: 0 1 2 P(X=x) 0.15 | 0.20 0.15 0.50

A: We want to find the mean  Mean=E(X)

Q: 1) y=-2+ 2cos 0 27 3n 1/24

A: The given function,     y=-2+2cos θ

Q: 1 0 0 0 1 -1 0 0 0 -1 - (Ь.) А — 1 -1 0 0 -1 0 -1 0 0 0 0 -1 1 0 0 1 - 1

A: Given: A=100001-100-11-100-10000-1-11001 To find: Jordan Canonical form of the matrices.

Q: 1 P = 1 1.5 1.5 0 0.5 0.5 (1) P2 = (2) P4

A:

Q: 2 1 0 2 1 -2 l2 1 4 [1 3 а11 а21 = [a21 [a31] 1 a11 a21- and A31=

A: here we need only matrix multiplication

Q: 1.1 3.1 2.4 39. 1.7 2.4 2.3 L0.6 -0.7 -0.1! ANSWER I

A:

Q: 2 6 6 1 0 0 [A|I] = 2 7 6 0 1 0 2 7 7 0 0 1 1 0 01 7 0 -3 1 1 0 0

A:

Q: 1 0 0 6 A 0 1 0 7 0 0 1 1 1 0 0* 0 1 1 0 0 0 0 1 В 1 0 0 4. 0 0 1 5 0 0 0 0 1 0 0 4. 0 0 1 5 0 0 0 0

A: A matrix is in reduced row-echelon form if the following holds: 1) All the leading elements are 1.…

Q: 1 2 01 0 0 33 1 0 0 0 5 -3 d. 0 1 0 0 0 1 2 3 4 5 1 0 7 1 3 0 0 0 0 1 LO 0 0 0 0 2. a. f. 10 10 01…

A: To Determine: which of the given matrices are in Row-Echelon or Row-reduced Echelon forms.

Q: (0.646. 0.5792) | (1.0.3183) (0. 0) (1.0) (2.0) |(1.43, 0) 04 06 08 (0. 0) (2. –0.6366) (1.564.…

A: From the given graphs, f(x)=g'(x) and h(x)=g''(x)because from the graph g(1) has maxima and g(2) has…

Q: nih ordak 1. 2. 0.1 0.05 0.0S 0.05 0.05 0.1 0.05 0.05 2 0.05 0.05 0.1 0.05

A: P(Y>X | X =2) = ?

Q: 1 2. [1 2 01 1 1 4 a. 66 +3 1 b. 0 1 0 c. 0 0 1 000 20 0 0 0 [1 5 [1 2 3] d. 0 1 e. 0 0 0 0 0 0 0 2…

A:

Q: -0.5] H-B-E 0.5 0.5 0.5 0.5 0.5 -0.5 -0.5 0.5 -0.5 0.5 -0.5

A: Follow the steps.

Q: 1 0 -2 0 0 0 1 0 0 0 0 0 0 3 1 0 0 1 0 0 0 0 0 0 0 1. Assume that A~ 0 -4 1

A:

Q: [1 T = 11 1. 1 9 0 9 -2 .a O 1 9 3 9 -2 .b O 3 9 1 9 0 .c 2 2 0 .d O 9 9. N O

A:

Q: solutions. 1 00 5 7 0 10 1 0 0 0 0 1 1 70 0 0 0 7) 0 0 0 1 0 0 0 2 1 1 1 1 1 0 0 1 0 0 0 0 0 1 0 2 7…

A:

Q: 4 0 1 1 [10 -1 1 4 1 1 -1 0 1 0 4 A = 4 B = 2 1 0 4 2 0 1 1 -1 0 [ 1. 2 4 1 0 (a) |A| (b) |B| (c) AB

A: Given: For (a),

Q: 1 3 P(X = x) 0.4 0.1 0.3 0.2

A: Given that  Probability distribution  X 0 1 2 3 P(X=x) 0.4 0.1 0.3 0.2

Q: 0 0 0 0 30 0 0 2 0 0 0 0 1 0 0 0 4 Evaluate: 0

A: The determinant of a matrix is found by expanding the determinant along a particular row or column…

Q: \0.8 0.3 ] 0.9 0.2 0.7 T = 0.1 =

A: Given

Q: 1. 1 3 P(x) 0.15 0.32 0.37 0.16

A: Given that  Probability mass function of X is  x 1 1 2 3 P(x) 0.15 0.32 0.37 0.16 Find…

Q: : p(y-2|<10) p(z <2) =0.9772 y- N(2,25) 0.4594 0.5944 O 0.9544

A: It is known that, Z score= (y-mean)/standard deviation. Given that, Mean= 2 and variance= 25  So…

Q: 3.2 [1.0 3.4 6. v = 2,0 0.4 トリ 1.4 -2.6 L4.8, -64

A:

Q: 0 1 2 3 4 5 P(X < x) 0.89 1 0.10 0.35 0.45 0.68 0.84 a. Calculate P(X< 4). c. Calculate P(3 < X <…

A:

Q: 1 0 01 0 0 0 1 1 0 0 0 0|. Find A[9]. 0 10 0 0 LO 0 гО О Let A 0 1 0

A: Here we will find out A[9]

Q: 1 0 1 A = 1 1 0 0 1 1 0 1 1 B = 1 01 1 0 1

A:

Q: 11. 1 2 3 4 5 P(x) 0.05 0.25 0.4 0.06

A: Note:Please repost remaining questions as I can author only 1 question as per my policyWe know that…

Q: 2 3 4 (a) 0 (b) 0 0 1 1 3 0 1 0 0 0 0 (c) 0 0 1 (d) 0 0 1 1 1 1 4 6 (e) 0 1 2 (f) 0 0 1 3 1 3

A:

Q: 1 0 0 1 c,c + 0 0 0 1

A: We have to find the determinant of the given matrix.…

Q: t1 = 1 t2 = 2 t3 = 3 t4 = 4 C1 = 11 C2 = 29 C3 = 65 C4 = 125 1 1 1 1 11 1 2 4 8 29 65 1 3 9 27 1 4…

A:

Q: Z• 0 • 1 6 0.00 0.25 0.50 0.75 1.00 4.

A:

Q: of 5 5 6 7 9. P(X = x) 0.2 0.2 0.2 0.1 0.3 8.

A:

Q: 2 3 4 Let A = 3 1 0 . Find A.adj (A). 0 2 1 17 0 17 0 17 Ob. 1 0 0 0 1 0 1

A: We will solve the following.

Q: 2 P(X) 0.17 0.46 0.16 0.16 0.05 Find P(X < 3). Round to TWO decimal places. O 0.16 O 0.79 O 0.21 O…

A: We use the given probability distribution table to find the required probability.

Q: et J ((et + 4)²-9)³/2 9)³3/2 dt.

A: See the details solution in below

Q: 1. Q = 3' + 2 2. Q = 0.5 · 30.75t 3. Q = 2/0.2 4. Q = t · 124 5. Q = 14t12 6. Q = 12 - 4

A:

Q: P(x) 0.15 0.35 0.40 6. 8. 10 0.10 P(x) 0.15 0.35 4 6. 0.40 18 0.10 P(x) 0.10 4 0.40 0.35 8. 0.15

A:

Q: (0 1 1 A=|1 0 1 1 1 0,

A:

Q: Compute the determinant of

A: We know that determinant of upper (lower) triangular matrix is the product of the diagonal entries.