The square loop in Figure P31.26 is made of wires with total series resistance 10.0 Ω. It is placed in a uniform 0.100-T magnetic field directed perpendicularly into the plane of the paper. The loop, which is hinged at each corner, is pulled as shown until the separation between points A and B is 3.00 m. If this process takes 0.100 s, what is the average current generated in the loop? What is the direction of the current?

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Chapter31: Faraday’s Law
Section: Chapter Questions
Problem 31.54AP: A circular loop of wire of resistance R = 0.500 and radius r = 8.00 cm is in a uniform magnetic...
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The square loop in Figure P31.26 is made of wires with total series resistance 10.0 Ω. It is placed in a uniform 0.100-T magnetic field directed perpendicularly into the plane of the paper. The loop, which is hinged at each corner, is pulled as shown until the separation between points A and B is 3.00 m. If this process takes 0.100 s, what is the average current generated in the loop? What is the direction of the current?

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Expert Solution
Step 1

Given:

Uniform magnetic field B = 0.1 T

Total series resistance R=10.0 Ω

Length of wire l=3 m.

time taken t = 0.1 s.

Physics homework question answer, step 1, image 1

Step 2

Induced E.M.F. is given as,

ε=-Ndϕdtε=-NddtBAcosθ=-NddtBAcos0ε=-NBdAdtε=-1×0.1×Af-Ai0.1ε=-(3×3sin60-32)ε=1.206 volt

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