College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Why is the following situation impossible? A skater glides along a circular path. She defines a certain point on the circle as her origin. Later on, she passes through a point at which the distance she has traveled along the path from the origin is smaller than the magnitude of her displacement vector
from the origin.
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- For the given vectors V₁ and V₂, determine V₁ + V₂, V₁ + V2. V₁-V₂, V₁x V2, V₁ V₂. Consider the vectors to be nondimensional. Assume V₁ = 15, V₂ = 21, a = 3, b = 5,0 = 22° Answers: V₁ + V₂ = i V₁ + V₂ = (i j+ k) V₁-V₂= (i j+ k) V₁xV₂ = (i j+ k) V₁ V₂ = i+ i+ i+ i i i iarrow_forwardAt a football game, imagine the line of scrimmage is the y-axis. A player, starting at the y-axis, runs 8.50 yards, back (in the −x-direction), then 15.0 yards parallel to the y-axis (in the −y-direction). He then throws the football straight downfield 55.0 yards in a direction perpendicular to the y-axis (in the +x-direction). What is the magnitude of the displacement (in yards) of the ball? yards (b) What if? The receiver that catches the football travels 64.0 additional yards at an angle of 45.0° counterclockwise from the +x-axis away from the quarterback's position and scores a touchdown. What is the magnitude of the football's total displacement (in yards) from where the quarterback took the ball to the end of the receiver's run?arrow_forwardA sailboat race course consists of four legs, defined by the displacement vectors A, B, C, and, as the drawing indicates. The magnitudes of the first three vectors are A = 2.90 km, B = 4.90 km, and C= 5.30 km. The finish line of the course coincides with the starting line. Using the data in the drawing, find (a) the distance of the fourth leg and (b) the angle (. (a) Number i 6.67 (b) Number 21.29 Units Units 0 0 23.0 7 B km + Finish- B 35.0 X 40.0° Startarrow_forward
- A sailboat race course consists of four legs, defined by the displacement vectors A, B, C, and, as the drawing indicates. The magnitudes of the first three vectors are A = 3.00 km, B = 5.10 km, and C = 4.80 km. The finish line of the course coincides with the starting line. Using the data in the drawing, find (a) the distance of the fourth leg and (b) the angle . (a) Number IA i (b) Number i Units Units 23.0 7 167 B Finish- B 35.0⁰ A 40.0° Startarrow_forwardA pilot needs to fy to a destination 350 km north of his current position in 2.0 hours. An air traffic controller tells him that the wind velocity (as seen on the ground) is 27 km/h [E34 °S]. a) Sketch the overall vectors of the plane to the ground, the plane to the air and the air to the ground. Write the equation for the velocity of the plane relative to the ground with the appropriate subscripts. b) What is the minimum speed that the pilot would need to fly if there was no wind? c) Determine the heading of the plane (in what direction must the pilot fly to compensate for the wind?). Show your work. Label your vectors and label x and y components. d) Determine the speed of the plane with respect to air that the pilot would need to take in order to reach the desired destination on time.arrow_forwardA bird flies 10 m at an angle of 45°. Then it flies 20 m at an angle of 135°. What are the x and y components of the bird's displacement vector at the end of the two flights? Group of answer choices (x,y) = (15 √ 2 ,−5 √ 2)m (x,y) = (−15 √ 2 ,5 √ 2)m (x,y) = (5 √ 2 , 15 √ 2) m (x,y) = (−5 √ 2 ,15 √ 2)m (x,y) = (5 √ 2 ,−15 √ 2)marrow_forward
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