EBK ENGINEERING MECHANICS
15th Edition
ISBN: 9780137616909
Author: HIBBELER
Publisher: VST
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Students have asked these similar questions
The shear leg derrick is used to haul the 200-kg net of
fish to the dock. Determine the compressive force along
eanch of the legs AB and CB and the tension in the
winch cable DB. Assume the force in each leg acts along
its axis.
a= 5.7 m
b= 3.7m
c= 2.2m
D
a
b
B
b
The shear leg derrick is used to
haul the 350-kg net of fish onto the
dock. Determine the compressive
force along each of the legs AB and
CB and the tension in the winch
cable DB. Assume the force in
each leg acts along its axis.
D
7.5 m
A
Z
4.5 m
3 m
3 m
B
4.5 m
The shear leg derrick is used to haul the 200-kg net of
fish to the dock. Determine the compressive force along
eanch of the legs AB and CB and the tension in the
winch cable DB. Assume the force in each leg acts along
its axis.
a=6.2 m
b=3.8m
c=1.8m
D
x
a
A
b
B
b
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- The shear leg derrick is used to haul the 200-kg net of fish onto the dock. Determine the compressive force along each of the legs AB and CB and the tension in the winch cable DB . Assume the force in each leg acts along its axis. 5.6 m 4m 4 m 2 m 2 marrow_forwardDetermine the tensions in the cable, normal force in the smoothsurfaces and the angle of inclination of the surface in the right ifthe block in the left and right weigh 300N and 500N,respectively. (Assume frictionless pulley)T =NA =NB =θB =arrow_forwardFind the forces in each member and specify if it is in tension or compression. At E is pin support and at D is link support. 5 m -link support B 5 m 5 m 5 m 5 m 5 m 5 m E 30 kN 20 kNarrow_forward
- A 415 kg safe is hanging from the apparatus below. Determine the tension in the cable. Dimension a=1.9 m and dimension b=2.5 m. The mass of the beam is 85 kg. Use g = 10 N/kg. Hint: Take torques about the hinge and use the perpendicular lever arm version of the torque equation (the sin theta version will work but will require more calculation).arrow_forwardThe horizontal force P is applied to the handle of the puller. Determine the resulting tension T in the chain in terms of P .arrow_forwardthe homogeneous cylinder of weight W=100 N rests in a frictionless right angled corner. determine the contact forces NA and NB angle is 30 degreesarrow_forward
- The bars AB and AC are joined by a pin at A and a horizontal cable. The vertical cable carrying the 100kNis attached to the pin at a. Determine the tension in the horizontal cable. Also, determine the reactions at the hinge and roller. Neglect the weights of the bars. a. Determine the tensile force (kN) on the cable.b. Determine the vertical reaction (kN) of the hinge. Indicate its direction, use positive value if it is upward and negative if it’s downward.c. Determine the horizontal reaction (kN) of the hinge. Indicate its direction, use positive value if it’s to the right and negative if it’s to the left.d. Determine the vertical reaction (kN) of the roller support. Indicate its direction, use positivevalue if it is upward and negative if it’s downward. Plsss show complete handwritten solution. Thanksss!!arrow_forwardDetermine the tension in the cable and the horizontal and vertical components of reaction of the pin A. The pulley at D is frictionless and the cylinder weighs 35 kg. The length are a= 1.5m,b= 1.5m,c= 1m.arrow_forwardThe bucket weighs 15 Ibs. determine the forces in the cables. 2.5 ft- 4.5 ft 3 ft 1,5 ft 3 ft -1.5 ft-arrow_forward
- The cable supports the three concentrated loads shown below. Determine the vertical positions yB and yB of points B and D and the tension in each segment of the cable. The loads are P= 400 lb P= 410 lb P3= 160 lb 4 ft 14 ft B P3 V P, P2 12 ft -- 20 ft - 12 ft -- 15 ftarrow_forwardThe 500-kg crate is supported by the three cables. Find the tension in cable AD. Kindly show correct FBDarrow_forwardDetermine the force in each member of the space truss given F-3 kN. Use positive to indicate tension and negative to indicate compression. Z D FAB= 5.35 FAC = 1.25 FAD = 1.25 FBC= 3.08 FBD = 3.08 FBE = 4 3 m E 2 m 3 m 4 m. x kN X KN X KN x kN x kN X KN B 5 m A F yarrow_forward
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