Suppose an astronaut has landed on Planet X. Fully equipped, the astronaut has a mass of 130 kg and when the astronaut gets on a scale, the reading is 53 N. what is the acceleration due to gravity on Planet X. (Answer to 2 decimal places)
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Suppose an astronaut has landed on Planet X. Fully equipped, the astronaut has a mass of 130 kg and when the astronaut gets on a scale, the reading is 53 N. what is the acceleration due to gravity on Planet X. (Answer to 2 decimal places)
From Newton's Second law,
We know that , Force(F)=mass(m)*acceleration (a)
F=m*a
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- The Scope and Scale of Physics Find the order of magnitude of the following physical quantities. (a) The mass of Earth’s atmosphere: 5.11018kg : (b) The mass of the Moon’s atmosphere: 25,000kg ; (c) The mass of Earth’s hydrosphere: 1.41021kg : (d) The mass of Earth: 5.971024kg : (e) The mass of the Moon: 7.341022kg : (f) The Earth-Moon distance (semimajor axis): 3.84108m : (g) The mean Earth-Sun distance: 1.51011m : (h) The equatorial radius of Earth: 6.38106m : (i) The mass of an electron: 9.111031kg : (j) The mass of a proton: 1.671027kg : (k) The mass of the Sun: 1.991030kg .The gravitational acceleration constant gx on Planet X can be approximated by determining the acceleration of an object assuming Newton's Law of Universal Gravitation. If gx = 3.8 m/s^2 , G = 6.7 x 10^-11 Nm^2/kg^2, and Planet X's radius is 4000 km, what is the approximate mass of planet X? Give answer in kg.According to Newton's law of universal gravitation, the attraction force between two bodies is given by: where mi and m2 are the masses of the bodies, r is the distance between the bodies, and G=6.67 × 10-" N-m²/kg² is the universal gravitational constant. Determine how many times the attraction force between the sun and the Earth is larger than the attraction force between the Earth and the moon. The distance between the sun and Earth is 149.6 x 10°m, the distance 28 between the moon and Earth is 384.4 × 10°m, mEarth = 5.98 x 10“ kg, = 2.0 x 10" kg, and mn =7.36 x 102 kg.
- Newton’s version of Kepler’s third law is P2 = 4 π2 / [G (M1 + M2)] · a3, where G is the gravitational constant, which is equal to 6.67*10-11 m3 kg-1 s-2. NASA's New Horizons mission found that Pluto's moon Charon orbits Pluto every 5.7 days at an average distance of 19200.0 km. What is the combined mass (in kg) of Pluto and Charon?The gravitational field strength of Venus is 8.9 N/kg. If its radius is 6.05 x 106 m, the mass of Venus, expressed in scientific notation, is a.b x 10cd kg. The values for a, b, c, and d are andNewton's Law of Gravitation says that the magnitude F of the force exerted by a body of mass m on a body of mass M is GmM F= where G is the gravitational constant and r is the distance between the bodies. (a) Find dF/dr. dF dr = What is the meaning of dF/dr? O dF/dr represents the amount of force per distance. O dF/dr represents the rate of change of the mass with respect to the distance between the bodies. O dF/dr represents the rate of change of the distance between the bodies with respect to the force. O dF/dr represents the rate of change of the mass with respect to the force. O dF/dr represents the rate of change of the force with respect to the distance between the bodies. What does the minus sign indicate? O The minus sign indicates that the force between the bodies is decreasing. O The minus sign indicates that as the distance between the bodies increases, the magnitude of the force decreases. O The minus sign indicates that as the distance between the bodies increases, the…
- The mass of Mars is 6.42 × 10^23 kg and when it is closest to earth it is 54 million km away. a) Convert the distance to meters using scientific notation and b) What is the gravitational force between Mars and earth at this distance ?Planet X has four times the diameter and five times the mass of earth. What is the ratio gx:ge of gravitational acceleration at the surface of Planet X to the gravitational acceleration at the surface of the earth? Please put the ratio on decimal form not on fraction form.Kepler's third law states that the relationship between the mean distance d (in astronomical units) of a planet from the Sun and the time t (in years) it takes the planet to orbit the Sun can be given by d^3 = t^2. (A). It takes Venus 0.616 years to orbit the Sun. Find the mean distance of Venus from the Sun (in astronomical units). (B). The mean distance of Jupiter from the Sun is 5.24 astronomical units. How many years does it take Jupiter to orbit the Sun?
- The mean distance of Mars from the Sun is 1.52 times that of Earth from the Sun. From Kepler’s law of periods, calculate the number of years required for Mars to make one revolution around the Sun; compare your answer with the value given in Appendix C.The gravitational field is another name for the acceleration due to gravity, depending on position, abbreviated as a. The gravitational field near the Earth's surface has the special value g = 9.8 m/s2. You can assume that the radius of the Earth is REarth = 6,400 km. Calculate the gravitational field from this formula, at a height of 585 km above the surface of the Earth. Enter the result in m/s2. Round to one digit after the decimal point (i.e., the same number of digits as in g = 9.8 m/s2). Hint: You can use either kilometers or meters for the values of REarth and R in this formula, as long as you use the same units for both. These units cancel out.When you are at a height x above the surface of the earth, your weight can be found by the following formula: W(x) = mg (1 + x/R) −2 , where m is the mass of your body, g is the acceleration due to gravity, and R is the radius of the earth. For example, W(0) is your weight when you are on the surface of the earth and W(R) is your weight when you are at the height R above the surface of the earth (yes, you are far away from the earth’s atmosphere). In this question, we will approximate W(0) and W(R). (a) Find L0(x), the linear approximation of W(x) at x = 0. (b) Use L0(x) to approximate W(0) and W(R). Which approximation is more accurate? Why? (c) Find LR(x), the linear approximation of W(x) at x = R. (d) Use LR(x) to approximate W(0) and W(R). Which approximation is more accurate? Why?
