Chapter 26, Problem 7Q

Problem 1:  A cell phone battery uses chemistry to create a charge separation between the terminals (anode and cathode). Such a battery is listed as having a capacity of Q = 7.5E-08 C.  Part (a)  How many free electrons does the battery contain, N? Part (b)  If there are 1.0 million electrons moving through the phone every second how long will the battery last in seconds? Part (c)  Current, I, is given in amps which are coulombs per second. What is the current passing through the phone?

A 5.00A Current runs through a 12-guage copper wire (diameter 2.05mm) and through a light bulb. Copper has 8.5 x 10^28 free electrons per cubic meter. (a) How many electrons pass through the light bulb each second? (b) What is the current density of the wire? (c) At what speed does a typical electron pass by any given point in the wire?

What current flows through a 2.45-cm-diameter rod of pure silicon that is 21.5 cm long, when 1.00 x 10³ V is applied to it? (Such a rod may be used to make nuclear particle detectors, for example.) 0.0365 X A What current flows through a 2.45-cm-diameter rod of pure silicon that is 21.5 cm long, when 1.00 x 10³ V is applied to it? (Such a rod may be used to make nuclear particle detectors, for example.) 0.000877 A What current flows through a 2.45-cm-diameter rod of pure silicon that is 21.5 cm long, when 1.00 x 10³ V is applied to it? (Such a rod may be used to make nuclear particle detectors, for example.) 0.00343 X A

What current flows through a 2.45-cm-diameter rod of pure silicon that is 21.5 cm long, when 1.00 x 10³ V is applied to it? (Such a rod may be used to make nuclear particle detectors, for example.) 0.0365 X A What current flows through a 2.45-cm-diameter rod of pure silicon that is 21.5 cm long, when 1.00 x 103 v is applied to it? (Such a rod may be used to make nuclear particle detectors, for example.) 0.000877 A

28 1 6.0 x 10 m3 1. Consider a cylindrical wire that has conduction electron density and radius 0.5 mm. An electric field with strength 7.5 x 10-4 creates a current of 4.8 x 10 electrons per second. a) What is the average drift speed for an electron? (include units) b) What is the average time in between electron collisions? fs (express your answer in femtoseconds)

What current flows through a 2.45-cm-diameter rod of pure silicon that is 21.5 cm long, when 1.00 x 10³ V is applied to it? (Such a rod may be used to make nuclear particle detectors, for example.) 0.0365 X A What current flows through a 2.45-cm-diameter rod of pure silicon that is 21.5 cm long, when 1.00 x 10³ V is applied to it? (Such a rod may be used to make nuclear particle detectors, for example.) 0.000877 A What current flows through a 2.45-cm-diameter rod of pure silicon that is 21.5 cm long, when 1.00 x 10³ V is applied to it? (Such a rod may be used to make nuclear particle detectors, for example.) 0.00343 X A What current flows through a 2.45-cm-diameter rod of pure silicon that is 21.5 cm long, when 1.00 x 10³ V is applied to it? (Such a rod may be used to make nuclear particle detectors, for example.) 0.0034 X A

The drift speed in a copper wire is 7.15 x 105 m/s for a typical electron current. Calculate the magnitude of the electric field E inside the copper wire. The mobility of mobile electrons in copper is 4.5 x 10-3 (m/s)/(N/C). (Note that though the electric field in the wire is very small, it is adequate to push a sizable electron current through the copper wire.) i N/C eTextbook and Media

In the figure,E₁ = 6.00 V, E₂= 12.0 V, R₁ = 100 S2, R₂ = 200 S, and R3 = 300 2. What are the (a) size and direction (up or down) of the current through R₁, the (b) size and direction (left or right) of the current through R2, and the (c) size and direction (left or right) of the current through R3? www Ro E₁ M R₁ www R3 E2

A charge crossing a surface due to a proton beam is given by Q = 5.0t3 + 3.0t2 + 8.0 where Q is measured in Coulombs and the time t is measured in seconds. What is the current due to the proton beam when t = 3.0 s. О (а) 459 A О (b) 153 А O (c) 297 A O (d) 99 A O (e) 56.7 A