A 100 pF capacitor is charged to a potential difference of 50 V, and the charging battery is disconnected. The capacitor is then connected in parallel with a second (initially uncharged) capacitor. If the potential difference across the first capacitor drops to 35 V, what is the capacitance of this second capacitor?

A parallel-plate capacitor is made of two square plates 40 cm on a side and 1 mm apart. The capacitor is connected to a 40-V battery. What is the energy stored in the capacitor? μJ. With the battery still connected, the plates are pulled apart to a separation of 2 mm. What is the energy stored in the capacitor now? μJ. This time, starting from situation in (a), with the batteries disconnected (but capacitors still charged), the plates are pulled apart to a separation of 2 mm. What is the energy stored in the capacitor now? μJ.

Two plates, each of area 5.30 cm², are 2.59 mm apart in a parallel plate capacitor. The space between the plates is filled with two different dielectric materials. The left half of the capacitor is filled with a material whose dielectric constant K, = 5.50. The right half of the capacitor is filled with a material of unknown dielectric value K2. The capacitance of this device is 7.95 pF. Find the value of K2. Additional Materials еBook e Show My Work (Optional) ?

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