A small, rigid object carries positive and negative 3.50-nC charges. It is oriented so that the positive charge has coordinates (-1.20 mm, 1.10 mm) and the negative charge is at the point (1.40 mm, –1.30 mm). (a) Find the electric dipole moment of the object. The object is placed in an electric field É 4.90 × 10° j) N/C. (b) Find the torque acting on the object. (c) Find the potential energy of the object-field system ing the orientation of the object can change, find the difference between the maximum and minimum (7.80 x 103 î – - when the object is in this orientation. (d) Assum- potential energies of the system.

Physics for Scientists and Engineers: Foundations and Connections
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Chapter24: Electric Fields
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A small, rigid object carries positive and negative
3.50-nC charges. It is oriented so that the positive
charge has coordinates (-1.20 mm, 1.10 mm) and the
negative charge is at the point (1.40 mm, –1.30 mm).
(a) Find the electric dipole moment of the object. The
object is placed in an electric field É
4.90 × 10* j) N/C. (b) Find the torque acting on the
object. (c) Find the potential energy of the object-field
system when the object is in this orientation. (d) Assum-
ing the orientation of the object can change, find
the difference between the maximum and minimum
= (7.80 × 10³ î –
potential energies of the system.
Transcribed Image Text:A small, rigid object carries positive and negative 3.50-nC charges. It is oriented so that the positive charge has coordinates (-1.20 mm, 1.10 mm) and the negative charge is at the point (1.40 mm, –1.30 mm). (a) Find the electric dipole moment of the object. The object is placed in an electric field É 4.90 × 10* j) N/C. (b) Find the torque acting on the object. (c) Find the potential energy of the object-field system when the object is in this orientation. (d) Assum- ing the orientation of the object can change, find the difference between the maximum and minimum = (7.80 × 10³ î – potential energies of the system.
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