Chapter 23.3, Problem 1EE

Hi, please also explain how you got the answer and also explain why that is the right answer. This is the right answer please explain. (A)

Hi, please help me solve (d) & (e). The answers for (a) to (c) have already been solved. I was told to post another question. Please provide step-by-step/clear/detailed solutions. I would really appreciate the help and am willing to give a thumbs up. Thank you!

Use the table to answer the question. Answer clearly, and label the answers so i know what answer goes to what part.

Hi, please also explain how you got the answer and also explain why that is the right answer. This is the right answer please explain. (B)

I don't doubt that the answer is correct but I'm having trouble following some of these steps. suppose you could somehow elaborate a little more on step two. a video would be awesome if possible...

Please help me with this problem and needed correct answer.. I can't even comment here so please don't send wrong Answers.. Wrong answers will simply unliked

Hi.  I still don't get it.  I'm not sure what sin and cos have to do with it.  But either way, I'm still stuck in the same place.   I don't know how you got from steps 3 and 4 to the next step.  One is for the x-axis and the other for the y-axis.  How did they end up merged together?  If you apply the Pythagorean theorem, you get either:v = sqrt{(vcos) 2 + (vsin) 2}  Then what?  Or you get:v = sqrt{(m1v1/m1+m2)2 + (m2v2/m1+m2)2}   Now what?  That "adding" step just looks like the Pythagorean theorem, with v2 being the c in c2 = a2 + b2, but what is going on on the other side of the equation?   I don't understand how in the denominator you went from:(m1 + m2)2 + (m1 + m2)2 to(m1 + m2)2It seems to me like (m1 + m2)2 + (m1 + m2)2 = 2(m1 + m2)2 Explain as if I didn't understand the algebra, because I think that's the issue here.

Get live help whenever you need from online tutors!Try bartleby tutor todayarrow_forward   Question e Get live help whenever you need from online tutors!Try bartleby tutor todayarrow_forward   Oh no! Our expert couldn't answer your question. Don't worry! We won't leave you hanging. Plus, we're giving you back one question for the inconvenience. Here's what the expert had to say: Hi and thanks for your question! Unfortunately, it looks incomplete. Please resubmit the question with the figure. We've credited a question back to your account. Apologies for the inconvenience. Ask Your Question Again 25 of 30 questions left this cycle Renews on 1/18/21 Question The spring shown in the figure is compressed 80.0 cm and is used to launch a 82kg. physics student along a frictionless track,  Given values are K= 85000 Nm and Height = 11m.        a)How far up the incline (in meters) does the student slide? Please use the values given in the question not in the diagram Now consider the track as…

Please put all the equations into the pictures and we’ll explained so I can understand:).