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Evaluating limits graphically Sketch a graph of f and use it to make a conjecture about the values of
20.
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- How do I do A, B, and C?arrow_forwardB. LIMITS at INFINITY Recall your lesson in Piece-wise function. X→C In this lesson, you must be able to differentiate between f(c) and lim f(x). In evaluating a function f(c), when you do DIRECT SUBSTITUTION, the result must be a DEFINED NUMBER (A NUMBER THAT EXIST), otherwise f(c) is UNDFINED. Contrary to lim f(x), when you do direct substitution, the answer maybe indeterminate 0/0 but THERE IS A WAY TO EVALUATE THE LIMIT USING MANY TECHNIQUES, otherwise lim f(x) DOES NOT EXIST. x→c X-C Let us examine the piece-wise function below. 0 1. f(-4) 2. f(-2) 3. f (0) The function is defined by the equation. 4. f (1) 5. f(2) 6. f (3) f(x) = 2+7, -4≤x≤-2 -2, 7. f (4) 8. f(7). -1, (x-2)², x-4 x-7 7 A Self-Regulated Learning Module 2arrow_forwardThe graph below is the function f(x) 4- 2- -3 -2 -1 -21 -51 Determine the following values. Enter "DNE" if a value does not exist, enter "oo" (lower case "o") if the limit approaches positive infinity, or "-oo" if the limit approaches negative infinity. lim f(x) = lim f(x) = lim f(2) = f(3)arrow_forwardLet |22² − a²| x-a 3 12 Find the lim f(x) x-a- Find the lim x→a+ if x < a (x + a)² if x ≥ a explanation how you get your answer in each case. 3 f(x) = f(a) x-a 4 For what value(s) of a, lim f(x) = lim f(x) = f(a). x-a x→a 5 where a is some constant. Show all your work or give a brief LO 6arrow_forward(1+4) Evaluate lim a brarrow_forwardusing this graph find the limit as x approaches -4- of f(x)arrow_forwardLet f(x)= 2x and g(x)=1- if lim f(x)= lim g(x) then k=| ( Drag and drop the correct option in the given 3x?+x box.) 2 -2 None of thesearrow_forwardx+ y3 Consider lim Which ONE of the following statements is TRUE? (x.y)-(1,-1) x+y A. None of the choices in the list. B. For every number e>0 there is a corresponding number 8>0 such that if point (x,y) is in the domain of f (x,y) = - and 00 there is a corresponding number 8>0 such that if point (x.y) is in the domain of f(x.y) = and 00 there is a correspomding number &>0 such that if point (x,y) is in the domain of f (x,y) = - x+y and 0<(x-1)2+ (y+1)? <8 and then |f (x,y) – 3|arrow_forwardSkz - 3, IS-1 S(x) = - 2+ k, 1>-1 find the value k such that lim f(x) exists. Given x-1arrow_forwardarrow_back_iosarrow_forward_iosRecommended textbooks for you
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