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A point charge is at the origin. With this point charge as the source point, what is the unit vector
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- A particle with charge q on the negative x axis and a second particle with charge 2q on the positive x axis are each a distance d from the origin. Where should a third particle with charge 3q be placed so that the magnitude of the electric field at the origin is zero?arrow_forwardLet there be three charges whose locations are given with respect to a coordinate system - Charge q1 = 32 µC is located at P1 (0, 29), Charge 2 = 13 µC is located at P2 (3, –7.5) and Charge g = 5 µC is located at P3 (-28, 0). All the coordinates have units in centimeters. a) Find the position vector that points from Pi to P3. I component Give your answer up to at least three significance digits. m y co Give your answer up to at least three significance digits. ent m b) Find the electric force on q, due to q3 only. I component of the electric force Give your answer up to at least three significance digits. N y component of the electric force Give your answer up to at least three significance digits. Narrow_forwardTwo charges lie in a line along the x axis. Charge 1 is q1 = 1.1 C and charge 2 is q2 = 2.15 C. They are each a distance of d = 0.093 m from the origin. What is the distance on the x-axis from the origin at which the electric field will be zero. Give your answer in meters.arrow_forward
- Two charges, one of 2.50μC and the other of -3.50μC, are placed on the x-axis, one at the origin and the other at x = 0.600 m, as shown in the figure (Figure 1). Find the position on the x-axis where the net force on a small charge +q would be zero. Express your answer in meters.arrow_forwardThe figure below shows a charged particle, with a charge of q = +38.0 nC, that moves a distance of d = 0.165 m from point A to point B in the presence of a uniform electric field E of magnitude 295 N/C, pointing right. A positive point charge q is initially at point A, then moves a distance d to the right to point B. Electric field vector E points to the right. (a) What is the magnitude (in N) and direction of the electric force on the particle? magnitude Ndirection (b) What is the work (in J) done on the particle by the electric force as it moves from A to B? J (c) What is the change of the electric potential energy (in J) as the particle moves from A to B? (The system consists of the particle and all its surroundings.) PEB − PEA = J (d) What is the potential difference (in V) between A and B? VB − VA = Varrow_forward1 Q É Απεργια This problem checks your understanding of the term in the equation for the electric field due to a point charge, Consider a charged particle at a point S whose coordinates are (1 m, 6 m, 10 m). We would like to find the electric field vector at a point P whose coordinates are (4 m, 7 m, 4 m). The "unit vector" is a vector that points from S to P that has length of 1 (or "unity"). What is its y component, in meters? (Your answer must be accurate to within 10%.)arrow_forward
- Three point charges are placed on the x-y plane: a +25.0 nC charge at the origin, a -25.0 nC charge on the x axis at 10.0 cm, and a +110 nC charge at the point (10.0 cm, 8.00 cm). Find the x component of the total electric force on the +110 nC charge due to the other two. (Express your answer to two significant figures.) Find the y component of the total electric force on the +110 nC charge due to the other two. (Express your answer to two significant figures.) Find the x component of the electric field at the location of the +110 nC charge due to the presence of the other two charges? (Express your answer to two significant figures.) Find the y component of the electric field at the location of the +110 nC charge due to the presence of the other two charges? (Express your answer to two significant figures.)arrow_forwardThe figure below shows a charged particle, with a charge of q = +39.0 nC, that moves a distance of d = 0.197 m from point A to point B in the presence of a uniform electric field E of magnitude 280 N/C, pointing right. A positive point charge q is initially at point A, then moves a distance d to the right to point B. Electric field vector E points to the right. (a) What is the magnitude (in N) and direction of the electric force on the particle? magnitude N direction --------------------------- (b) What is the work (in J) done on the particle by the electric force as it moves from A to B? J (c) What is the change of the electric potential energy (in J) as the particle moves from A to B? (The system consists of the particle and all its surroundings.) PEB − PEA = J (d) What is the potential difference (in V) between A and B? VB − VA =…arrow_forwardSeveral species of bacteria, including Geobacter metallireducens, have been shown to "eat" electrons, bypassing the usual process of metabolizing sugar to obtain energy. During this process, the bacteria, which already have negatively charged cell membranes, acquire an even larger net negative charge, typically between 10.0e and 85.0e in magnitude. Individual Geobacter are typically 4.00 µm in diameter. What are the magnitude and the direction of the electric field of a bacterium with a net negative charge of magnitude 30.0eat a distance of 1.00 mm from the microbe? (a)the magnitude (in N/C) _________N/C (b)the direction radially outward radially inward What are the magnitude and the direction of the electric force on a second bacterium of net negative charge 55.0e a distance of 1.00 mm from the first bacterium? (c) the magnitude (in N) ______N (d)the direction away from the first bacterium towards the first bacteriumarrow_forward
- An electron is near a positive ion of charge +9e and a negative ion of charge −8e (see the figure below). (Take a = 4.15 µm, b = 3.76 µm, and ? = 61.0°.) (a) Find the magnitude and direction of the resultant force on the electron. (Let right be the +x-direction. Measure the angle counter-clockwise from the +x-axis.) Find Magnitude and direction (b) Find the magnitude and direction of the electron's instantaneous acceleration (Let right be the +x-direction. Measure the angle counter-clockwise from the +x-axis.) Find Magnitude and directionarrow_forwardThree point charges are arranged as shown in the figure below. Find the magnitude and direction of the electric force on the particle q = 5.06 nC at the origin. (Let r,, = 0.305 m.) magnitude direction 257.87 ° counterclockwise from the +x axis 6.00 nC 0.100 m -3.00 nC|arrow_forwardThe figure below shows a charged particle, with a charge of q = +38.0 nC, that moves a distance of d = 0.185 m from point A to point B in the presence of a uniform electric field E of magnitude 245 N/C, pointing right. A positive point charge q is initially at point A, then moves a distance d to the right to point B. Electric field vector E points to the right. (a) What is the magnitude (in N) and direction of the electric force on the particle? magnitude Ndirection ---Select--- toward the right toward the left The magnitude is zero. (b) What is the work (in J) done on the particle by the electric force as it moves from A to B? J (c) What is the change of the electric potential energy (in J) as the particle moves from A to B? (The system consists of the particle and all its surroundings.) PEB − PEA = J (d) What is the potential difference (in V) between A and B? VB − VA = Varrow_forward
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning