A 1.00-L insulated bottle is full of tea at 91.5A?°C. You pour out a mug of tea and immediately screw the stopper back on the bottle. Find the change in temperature of the tea remaining in the bottle that results from the admission of air at room temperature. (Let the room temperature be 20.0A?°C and assume that you poured out 180 cm3 of tea. Take the molar mass of air as 28.9 g/mol and A?air = 1.20 10-3 g/cm3. Here we define a "monatomic ideal gas" to have molar specific heats CV = (3/2)(R) and CP =(5/2)(R), and a "diatomic ideal gas" to have CV = (5/2)(R) and CP = (7/2)(R)). A?°C

A 1.00-L insulated bottle is full of tea at 91.5A?°C. You pour out a mug of tea and immediately screw the stopper back on the bottle. Find the change in temperature of the tea remaining in the bottle that results from the admission of air at room temperature. (Let the room temperature be 20.0A?°C and assume that you poured out 180 cm3 of tea. Take the molar mass of air as 28.9 g/mol and A?air = 1.20 10-3 g/cm3. Here we define a "monatomic ideal gas" to have molar specific heats CV = (3/2)(R) and CP =(5/2)(R), and a "diatomic ideal gas" to have CV = (5/2)(R) and CP = (7/2)(R)). A?°C

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter1: Temperature And Heat

Section: Chapter Questions

Problem 49P: The height of the Washington Monument is measured to be 170.00 m on a day when the temperature is...

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