At 20.0°C, an aluminum ring has an inner diameter of 5.000 0 cm and a brass rod has a diameter of 5.050 0 cm. (a) If only the ring is warmed, what temperature must it reach so that it will just slip over the rod? (b) What If? If both the ring and the rod are warmed together, what tem- perature must they both reach so that the ring barely slips over the rod? (c) Would this latter process work? Explain. Hint: Consult Table 19.2 in the next chapter.

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Chapter18: Temperature
Section: Chapter Questions
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TABLE 19.2 Latent Heats of Fusion and Vaporization
Latent Heat
of Fusion
(J/kg)
Substance
Helium
Oxygen
Nitrogen
Ethyl alcohol
Water
Sulfur
Lead
Melting
Point (°C)
-272.2
-218.79
-209.97
-114
0.00
119
327.3
660
5.23 x 10¹
1.38 x 104
2.55 X 10¹
1.04 x 105
3.33 x 105
3.81 x 104
960.80
1 063.00
1 083
2.45 x 10¹
3.97 X 105
8.82 x 10
6.44 x 10¹
1.34 x 105
Boiling
Point (°C)
-268.93
-182.97
-195.81
78
100.00
444.60
1 750
2 450
Latent Heat
of Vaporization (J/kg)
2 193
2 660
1 187
2.09 x 10¹
2.13 X 10²
2.01 X 10²
8.54 x 105
2.26 × 106
3.26 X 105
Aluminum
Silver
Gold
Copper
*Helium does not solidify at atmospheric pressure. The melting point given here corresponds to a pressure of 2.5 MPa.
8.70 x 105
1.14 x 10²
106
2.33 X
1.58 x 10
5.06 X 106
Transcribed Image Text:TABLE 19.2 Latent Heats of Fusion and Vaporization Latent Heat of Fusion (J/kg) Substance Helium Oxygen Nitrogen Ethyl alcohol Water Sulfur Lead Melting Point (°C) -272.2 -218.79 -209.97 -114 0.00 119 327.3 660 5.23 x 10¹ 1.38 x 104 2.55 X 10¹ 1.04 x 105 3.33 x 105 3.81 x 104 960.80 1 063.00 1 083 2.45 x 10¹ 3.97 X 105 8.82 x 10 6.44 x 10¹ 1.34 x 105 Boiling Point (°C) -268.93 -182.97 -195.81 78 100.00 444.60 1 750 2 450 Latent Heat of Vaporization (J/kg) 2 193 2 660 1 187 2.09 x 10¹ 2.13 X 10² 2.01 X 10² 8.54 x 105 2.26 × 106 3.26 X 105 Aluminum Silver Gold Copper *Helium does not solidify at atmospheric pressure. The melting point given here corresponds to a pressure of 2.5 MPa. 8.70 x 105 1.14 x 10² 106 2.33 X 1.58 x 10 5.06 X 106
V
13. At 20.0°C, an aluminum ring has an inner diameter of
QIC 5.000 0 cm and a brass rod has a diameter of 5.050 0 cm.
(a) If only the ring is warmed, what temperature must
it reach so that it will just slip over the rod? (b) What If?
If both the ring and the rod are warmed together, what tem-
perature must they both reach so that the ring barely slips
over the rod? (c) Would this latter process work? Explain.
Hint: Consult Table 19.2 in the next chapter.
Transcribed Image Text:V 13. At 20.0°C, an aluminum ring has an inner diameter of QIC 5.000 0 cm and a brass rod has a diameter of 5.050 0 cm. (a) If only the ring is warmed, what temperature must it reach so that it will just slip over the rod? (b) What If? If both the ring and the rod are warmed together, what tem- perature must they both reach so that the ring barely slips over the rod? (c) Would this latter process work? Explain. Hint: Consult Table 19.2 in the next chapter.
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