a)
Interpretation: To determine whether
Concept introduction: Depending on the ability of the ion to react with water the nature of the salt can be determined. If the cation is a strong base and the anion is a strong acid, then the solution or the salt will be neutral. If the cation is a weak base and the anion is a strong acid, then the solution will be acidic. If the cation is a strong base and the anion is a weak acid, then the solution will be basic.
b)
Interpretation: To determine whether
Concept introduction: Depending on the ability of the ion to react with water the nature of the salt can be determined. If the cation is a strong base and the anion is a strong acid, then the solution or the salt will be neutral. If the cation is a weak base and the anion is a strong acid, then the solution will be acidic. If the cation is a strong base and the anion is a weak acid, then the solution will be basic.
c)
Interpretation: To determine whether
Concept introduction Depending on the ability of the ion to react with water the nature of the salt can be determined. If the cation is a strong base and the anion is a strong acid, then the solution or the salt will be neutral. If the cation is a weak base and the anion is a strong acid, then the solution will be acidic. If the cation is a strong base and the anion is a weak acid, then the solution will be basic.
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CHEMISTRY:MOLECULAR...V.2 W/ACCESS
- What is the freezing point of vinegar, which is an aqueous solution of 5.00% acetic acid, HC2H3O2, by mass (d=1.006g/cm3)?arrow_forwardWhich of the following species can be Brønsted–Lowry bases: (a) Al(OH) 3; (b) Br −; (c) NH 4+; (d) CN −?arrow_forwardDetermine the pH of each of the following solutions (Ka and Kb values can be found in the appendices of your textbook or online): (a) 0.045 M hypochlorous acid; (b) 0.0068 M phenol; (c) 0.080 M hydroxylamine.arrow_forward
- The compound methylamine is a weak base like ammonia. A solution contains 0.199 M CH;NH3* and 0.117 M methylamine, CH3NH2. The pH of this solution isarrow_forwardWhat is the conjugate base of boric acid, B(OH)3? (A) OH– (B) B(OH)4– (C) B(O)(OH)22– (D) B(H2O)(OH)2+arrow_forwardPropionic acid, HC3H5O2, has Ka= 1.34 x 10–5. (a) What is the molar concentration of H3O+ in 0.15 M HC3H5O2 and the pH of the solution? (b) What is the Kb value for the propionate ion, C3H5O2–? (c) Calculate the pH of 0.15 M solution of sodium propionate, NaC3H5O2. (d) Calculate the pH of solution that contains 0.12 M HC3H5O2 and 0.25 M NaC3H5O2.arrow_forward
- Calculate the pH of 0.10 M (COOH)2 (aq), oxalic acid. Ka1 = 5.9 × 10–2 ; Ka2 = 6.4 × 10–5.arrow_forwardIn the following reactions, identify the Lewis acid and the Lewis base. (a) AlCl3 + Cl¯ → AICI, (b) CH;COOH(aq) + NH3(aq) → CH;COO (aq) + NH (aq) (c) Co³* (aq) + 6F (aq) → [CoF, j*¯ (aq)arrow_forward(a) Hydrogen peroxide, H2O2, is a Brønsted Lowry acid. It is used as an antiseptic and bleaching agent. Write the formula for the conjugate base of hydrogen peroxide. (b) Hydrazine, N2H4, is a Brønsted-Lowry base used as a rocket fuel. Write the formula for the conjugate acid of hydrazine. (c) Phenol, HOC6H5, is a Brønsted-Lowry acid used to make plastics, nylon, and slimicides. Write the formula for its conjugate base. (d) Aniline, C6H5NH2, is a Brønsted-Lowry base used to make polyurethane. Write the formula for its conjugate acid.arrow_forward
- You are given two glasses of water that have different temperatures. The temperature of the first glass is at 298 K, while the second glass has a temperature of 303 K. It has been determined that the Kw value for the second glass of water is 1.47 x 10-¹4. Which of the following statements is true? (a) The pH of the room temperature glass is higher, but both glasses have the same acidity. (b) The room temperature glass of water has a higher pH, and is more basic than the other glass of water. (c) Both glasses of water are neutral, so both will have a pH of 7.00. (d) The room temperature water has a lower pH, so is more acidic. (e) The warmer glass of water has a lower pH, and is more acidic than the other glass of water.arrow_forwardWrite the formula for the conjugate base of each of the following acids: (a) CH,CICOOH, (b) HIO4, (c) H,PO4, (d) H,PO, (e) HPO, (f) H,SO,, (g) HSO,, (h) HIO3, (i) HSO,, (j) NH, (k) H,S, (1) HS, (m) HCIO. A58arrow_forwardCalculate the pH of a solution by dissolving 1.90 g of sodium acetate, CH3COONa, in 71.0 mL of 0.15 M acetic acid, CH3COOH(aq). Assume the volume change upon dissolving the sodium acetate is negligible. Last of CH3COOH is 1.75 x 10^-5arrow_forward
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