Chemistry for Today: General  Organic  and Biochemistry
Chemistry for Today: General Organic and Biochemistry
9th Edition
ISBN: 9781337514576
Author: Seager
Publisher: Cengage
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Chapter 17, Problem 17.59E
Interpretation Introduction

Interpretation:

The reason as to why hexanal and 1-hexanol are liquids at room temperature but glucose is solid is to be stated.

Concept introduction:

Carbohydrates are one of the essential macronutrients in our diet. It is the major source of energy and is important for balanced diet. Monosaccharides are the sub-category of carbohydrates that are small units of simple sugars. Glucose is a monosaccharide. The formula for glucose is C6H12O6.

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Consider the molecule shown below. Which statement is FALSE? H H HO H- CHO -OH -OH -H -OH CH₂OH This is an aldohexose. This is a D isomer This molecule has five chiral carbons. This is a monosaccharide. Humans can easily digest this compound.
Suppose the hydrogens on the OH groups in glucose were replaced with methyl groups, CH3. Would you expect the water solubility of the resulting molecule to be higher than, lower than, or about the same as glucose?
Classify the following disaccharide. a. beta 1-2 disaccharide b. alpha 1-4 disaccharide c. alpha 1-6 disaccharide d. alpha 1-2 disaccharide e. beta 1-4 disaccharide f. beta 1-6 disaccharide

Chapter 17 Solutions

Chemistry for Today: General Organic and Biochemistry

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