(a)
Interpretation:
An explanation corresponding to the fact that pyrrole is isoelectronic with the cyclopentadienyl anion is to be stated.
Concept introduction:
Isoelectronic species are those species that have same number of electrons or same electronic configuration. These species have same chemical properties.
(b)
Interpretation:
The difference between the compound cyclopentadienyl anion and pyrrole is to be determined.
Concept introduction:
Bases are the molecules that can accept the proton by sharing its lone pair of electrons. The atoms that are basic in a molecule always have the lone to lone pair to accept the proton. Some of the molecules may contain more than one basic atom.
The lone pairs that are present in the molecule can be neutral or anionic atoms.
(c)
Interpretation:
The resonance structures that show the charge distribution on the pyrrole structure are to be represented.
Concept introduction:
The concept of resonance related to the stability of the molecules. Resonance structures show the movement of delocalized electrons in the molecule, when the bonding of the molecule cannot express by the single structures.
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EP ORGANIC CHEMISTRY -MOD.MASTERING 18W
- 2. Draw the each structures. For each structure, obtain the following information:a. Chargeb. Bond dipolesc. Over-all dipolearrow_forwardWhich of the following molecules is anti-aromatic? A. Cyclopentadienyl cation B. cycloheptatriene C. silopentadiene D. cycloheptatrienyl cation E. cyclopentadienyl anionarrow_forward3. What is the л-energy diagram of the Friedel-Craft reaction intermediate? a. b. C. d. AIC13 Arenium ? e. not a.-d.arrow_forward
- d. 12. What is the simplest fused aromatic hydrocarbon? a. Naphthalene b. 1,2-Benzylpyrene c. Methylbenzene d. Cyclobenzene 13. In electrophilic aromatic substitution reactions, a phenyl substituent on the aromatic ring is a. a deactivator and a m-director b. a deactivator and an o,p-director c. an activator and an o,p-director d. none of the above 14. Acetylide ion formation requires a strong base like NaNH2 which in turn is made using ammonia and Na. The catalyst used in this reaction is a. Cu b. Fe C. Pt d. Pd 15. Hydroboration-Oxidation of terminal alkyne results in the formation of an a. Aldehyde by Markovnikov mechanism b. Ketone by anti-Markovnikov mechanism c. Enol by Markovnikov mechanism d. Aldehyde by anti-Markovnikov mechanism 16.p-Methoxybenzaldehyde can be prepared from anisole using the Gatterman- Koch formylation. What mixture of reagents is necessary for this process? a. CO, HCI, AICI3, CuCI b. CO, SO3, H2SO4 CO2, HCI, AICI3 d. CO2, SO3, H2SO4 e. CO2, HNO3, H2SO4 C.arrow_forwardQUESTION 2 The preparation of a Wittig salt from an alky halide and triphenylphosphine proceeds by a(n) O A. E2 O B. Sn2 OC. E1 O D. free radical O E. Sn1 mechanism. QUESTION 3 Which resonance structure is more reactive as a nucleophile? Ph Ph O A. 1 O B. 2 OC. both are equally reactive Click Save and Submit to save and submit. Click Save All Answers to save all answers. o search F10 F1 F2 F3 F4 F5 F6 23 2 3 4. 7 8 W Y UIarrow_forwardquestion about reagentsarrow_forward
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- Which or which of the statements given below is correct. I) Maleic anhydride is a carboxylic acid derivative and its reaction with water is a reduction reaction. II) Fumaric acid and maleic acid are stereoisomers of each other III) Since fumaric acid has a more stable structure than maleic acid, its boiling point is higher. A. Solo I B. I and III C. II and III D. I, II, III E. Solo IIIarrow_forwardI. II. III. V. IV. A. m-isopropylnitrobenzene B. o-isopropyinitrobenzene You are given the following compounds. 1. Pyridine 2. cyclobutadiene The aromatic compounds from the above list are: A. 1,2,3 B. 2,3,4 IUPAC name for mesitylene is: A. 1,2,3-trimethylbenzene 1,2,4-trimethylbenzene B. C. 1,3,5-trimethylbenzene D. 1,3,4-trimethylbenzene E. 1,4,5-trimethylbenzene Identify the antiaromatic compounds from the following list: 3. thiophene 1. cyclobutadiene 2. cyclopropenium anion 5. cyclopentadienyl cation A. 1,2,3 ABCDE C. p-isopropylnitrobenzene D. mixture of o-and p-isopropylbenzene E. The recovery of nitrobenzene A. B. C. 3. anthracene B. 3,4,5 C. 1,2,5 D. 3,4,5 E. 2,3,4 Nitrobenzene was reacted with n-propyl chloride in the presence of aluminum chloride as a catalyst. The product formed is: C. 1,2,3,4 iso-butylbenzene sec-butylbenzene tert-butylbenzene D. n-butylbenzene Benzene was reacted with isobutyl chloride in the presence of aluminum chloride as a catalyst. The product formed…arrow_forwardGive a clear handwritten answer with explanation neededarrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning