EBK ORGANIC CHEMISTRY-PRINT COMPANION (
4th Edition
ISBN: 9781119776741
Author: Klein
Publisher: WILEY CONS
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Draw a structural formula of an alkene or alkenes (if more than one) that undergo acid-catalyzed hydration and without rearrangement give 2-methyl-2-butanol as the MAJOR product.
You do not have to consider stereochemistry.
You do not have to explicitly draw H atoms.
If more than one structure fits the description, draw them all.
Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner.
Separate structures with + signs from the drop-down menu.
- For the dehydration shown, use curved arrows to show the formation of the carbocation intermediate in the presence of sulfuric acid H2SO4H2SO4, then draw the structures of the minor and major products of the elimination.
Picture: Cyclohexane (no double or triple bonds) with a methyl group and an alcohol group (HO 4e- on O) on C1 (bottom) reacting with H2SO4 -> "Major and Minor Products"
-The H2SO4H2SO4 is abbreviated as H+H+ in the drawing module. Do not delete any pre‑drawn bonds, charges, or lone pairs. If you accidentally make a mistake, remove the last change by using the undo button on the lower left or revert the drawing palette to the original state by selecting the More menu, then select Reset Drawing.
Step 1: Use curved arrows to complete the protonation mechanism of the alcohol.
Step 2: Use a curved arrow to show the formation of the carbocation intermediate for the elimination.
(Picture 1)
-Step 3: This tertiary carbocation intermediate readily undergoes…
Shown below is a carbocation intermediate in an electrophilic addition reaction of HCl with an alkene.
For the conformation shown, select each hydrogen whose bond to carbon is aligned for effective hyperconjugation with the vacant p orbital on the positively charged
carbon. Each adjacent carbon will have only one C-H bond so aligned.
• Gray = C; white = H; red = 0; blue = N; dark green = Cl; brown =Br; light green =F; purple = I; yellow = S; orange = P.
• Double click to select atoms.
• You can zoom in and out using the mouse scroll wheel (or pinch to zoom on touch screens).
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- CH3 CH3 Br- Br2 .CH3 CH2Cl2 CH3 H3C H3C Br Electrophilic addition of bromine, Brɔ, to alkenes yields a 1,2-dibromoalkane. The reaction proceeds through a cyclic intermediate known as a bromonium ion. The reaction occurs in an anhydrous solvent such as CH,Cl,. In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product. Due to steric clashes, the bromide ion always attacks the carbon from the opposite face of the bromonium ion so that a product with anti stereochemistry is formed. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions CH3 CH3 CH3 CH3 H3C H3C :Br: :Br:arrow_forwardA certain hydrocarbon had the molecular formula C16H26 and contained two triple bonds. Ozonolysis gave CH3(CH2), CO₂H and HO₂CCH2CH2CH2CH2CO₂H as the only products. Draw a reasonable structure for this hydrocarbon. Click and drag to start drawing a structure. D:arrow_forwardDraw a structural formula of an alkene or alkenes (if more than one) that undergo acid-catalyzed hydration and without rearrangement give 1-methylcyclohexanol as the major product. You do not have to consider stereochemistry. • You do not have to explicitly draw H atoms. ● If more than one structure fits the description, draw them all. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. Separate structures with + signs from the drop-down menu. ● ● ✓ ? ChemDoodleⓇ n [ ]#arrow_forward
- If you were using the following reaction to produce acetone (CH3COCH3) CH3COCH2COOH → CH3COCH3 + CO2 what would be the overall atom efficiency of this reactionarrow_forward(1) (2) The electrophilic addition of HBr to the alkene (3) gives rise to a bromoalkane product as shown in Figure 1. Draw the structure of the bromoalkane product. Draw the structure of the intermediate species leading to this product. • Identify which step of the reaction is the fast step and which is the slow step. Using the curly arrow notation draw a mechanism for this reaction. Step 1 Step 2 Н-Br [ Intermediate Species ] + Bromoalkane (3)arrow_forwardFill in the following missing organic structures. Consider stereochemistry (R/S and/or E/Z –cis/trans) and possible carbocation rearrangements.arrow_forward
- Draw a structural formula of an alkene or alkenes (if more than one) that undergo acid-catalyzed hydration and without rearrangement give 1-methylcyclohexanol as the major product. • You do not have to consider stereochemistry. • You do not have to explicitly draw H atoms. • If more than one structure fits the description, draw them all. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. Separate structures with + signs from the drop-down menu. ● AAVII -85 ? ChemDoodleⓇ Y [Farrow_forwardDraw a structural formula of an alkene or alkenes (if more than one) that undergo acid-catalyzed hydration and without rearrangement give 1-methylcyclohexanol as the major product. • You do not have to consider stereochemistry. • You do not have to explicitly draw H atoms. • If more than one structure fits the description, draw them all. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. Separate structures with + signs from the drop-down menu. ● VIL ? ChemDoodle Ⓡ Qt Sn [Farrow_forward(dehydrobromination) A chemist carried out an elimination reaction of 1,1-dimethyl-2- bromocyclopentane. The chemist expected the reaction to yield alkene Z as product. However, alkene Z DID NOT form. Instead, three alkenes were produced: one alkene was the major product, the other two alkenes was the minor products. What was the major alkene product that formed? Br Select one: A. I B. II C. IV D. III alcohol HEAT || Z = + (HBr) IVarrow_forward
- H3C CH3 H3C NA C→XT Br Br₂ CH₂Cl₂ H3C Electrophilic addition of bromine, Br₂, to alkenes yields a 1,2-dibromoalkane. The reaction proceeds through a cyclic intermediate known as a bromonium ion. The reaction occurs in an anhydrous solvent such as CH₂Cl₂. CH3 Br In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product. Due to steric clashes, the bromide ion always attacks the carbon from the opposite face of the bromonium ion so that a product with anti stereochemistry is formed. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions Br CH3 H3C CH3arrow_forwardМЕСНANISMS 1,2-epoxy-1-methylcyclopentane undergoes both acid-catalyzed and base-catalyzed opening of the epoxide ring to form two different products. > Using ethanol as the solvent and an appropriate acid, show the steps in the acid catalyzed mechanism, writing structures for all products of the steps. Circle the major product(s). > Using ethanol as the solvent and an appropriate base, show the steps in the base- catalyzed mechanism, writing structures for all products of the steps. Circle the major product(s). 1,2-epoxy-1-methylcyclopentane CH3arrow_forwardIIIC) trans-cyclooctene can be synthesized from cis-cyclooctene with UV light (hv). Use orbital line diagram to show electronic excitation and arrow-pushing to show how this reaction can occur photochemically. hyarrow_forward
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