This extreme value problem has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to find the extreme values of the function subject to the given constraint. f(x, y) = xy;    25x2 + y2 = 50

Q6: Create a model using an Algebraic Constraint block to find a solution for the non-linear equation: F(x) = 3x-2x + 6x – 8

Minimise x2+y−2xyx2+y−2xy subject to the constraint y=1

Find the minimum of the function f(x) = x³ – 5x³ – 13x + 4 using quadratic interpolation. Use x0 = 0, x1 = 2, x2 = 4 as an initial quess. Tip: Make table with x0,x1,x2,x3, f (x0),ƒ (x1), f(x2),f(x3). Remove the worst quess from these and arrange 20,x1,x2 values in ascending order then conducts iteration ie. calculate new x3 and f (x3) iterate again until you get two same į values with for example five decimal points. Insert the numerical value of minium value for f(x) here f_x = -30.176 Verify your answer here fi = -30.176