ORGANIC CHEMISTRY (LL) W/WILEYPLUS NEXT
12th Edition
ISBN: 9781119664635
Author: Solomons
Publisher: WILEY
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Textbook Question
Chapter 14, Problem 30P
For each of the pairs below, predict specific aspects in their
(a)
(b)
(c)
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Chapter 14 Solutions
ORGANIC CHEMISTRY (LL) W/WILEYPLUS NEXT
Ch. 14 - PRACTICE PROBLEM 14.1 Provide a name for each of...Ch. 14 - Prob. 2PPCh. 14 - Prob. 3PPCh. 14 - Practice Problem 14.4 Apply the polygon-and-circle...Ch. 14 - Practice Problem 14.5 Apply the polygon-and-circle...Ch. 14 - Practice Problem 14.6 1,3,5-Cycloheptatriene is...Ch. 14 - Prob. 7PPCh. 14 - Prob. 8PPCh. 14 - Practice Problem 14.9 In 1967 R. Breslow (of...Ch. 14 - Prob. 10PP
Ch. 14 - Practice Problem 14.11 In addition to a signal...Ch. 14 - PRACTICE PROBLEM 14.12
Azulene has an appreciable...Ch. 14 - Practice Problem 14.13 (a) The -Sh group is...Ch. 14 - Practice Problem 14.14
Explain how NMR...Ch. 14 - PRACTICE PROBLEM 14.15 Four benzenoid compounds,...Ch. 14 - Prob. 16PCh. 14 - Write structural formulas and give acceptable...Ch. 14 - Prob. 18PCh. 14 - Prob. 19PCh. 14 - Prob. 20PCh. 14 - Which of the hydrogen atoms shown below is more...Ch. 14 - 14.22 The rings below are joined by a double bond...Ch. 14 - Prob. 23PCh. 14 - 14.24 (a) In 1960 T. Katz (Columbia University)...Ch. 14 - Prob. 25PCh. 14 - Prob. 26PCh. 14 - 14.27 5-Chloro-1,3-cyclopentadiene (below)...Ch. 14 - Prob. 28PCh. 14 - Furan possesses less aromatic character than...Ch. 14 - 14.30 For each of the pairs below, predict...Ch. 14 - Assign structures to each of the compounds A, B,...Ch. 14 - Prob. 32PCh. 14 - Give a structure for compound F that is consistent...Ch. 14 - Prob. 34PCh. 14 - Prob. 35PCh. 14 - The IR and 1H NMR spectra for compound X(C8H10)...Ch. 14 - Prob. 37PCh. 14 - Prob. 38PCh. 14 - 14.39 Given the following information, predict the...Ch. 14 - Consider these reactions: The intermediate A is a...Ch. 14 - Prob. 41PCh. 14 - Compound E has the spectral features given below....Ch. 14 - Draw all of the molecular orbitals for...Ch. 14 - Prob. 1LGPCh. 14 - Prob. 2LGPCh. 14 - 3. The NMR signals for the aromatic hydrogens of...Ch. 14 - Prob. 4LGPCh. 14 - Prob. 5LGP
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- Draw the NMR spectra you would expect for the following compounds.(a) (CH3)2CH¬O¬CH(CH3)2arrow_forwardCompound C has the molecular formula C5H8O. The IR, 1H, 13C, and DEPT NMR spectra of this compound are shown below. (a) Calculate the double bond equivalent of compound C and briefly explain what the values obtains represents. Interpret the IR spectrum. (b) Based on the information provided, determine the structure of compound D.arrow_forwardCompound A with molecular formula C6H10 has two peaks in its 1H NMR spectrum, both of which are singlets (with ratio 9 : 1). Compound A reacts with an acidic aqueous solution containing mercuric sulfate to form compound B, which gives a positive iodoform test and has an 1H NMR spectrum that shows two singlets (with ratio 3 : 1). Identify A and B.arrow_forward
- Compound A has molecular formula C5H10O. It shows three signals in the 1H-NMR spectrum - a doublet of integral 6 at 1.1 ppm, a singlet of integral 3 at 2.14 ppm, and a quintet of integral 1 at 2.58 ppm. Suggest a structure for A and explain your reasoning.arrow_forward(b) One isomer of dimethoxybenzoic acid has 1H NMR spectrum dµ (ppm) 3.85 (6H, s), 6.63 (1H, t, J 2 Hz), and 7.17 (2H, d, J 2Hz), One isomer of coumalic acid has 'H NMR spectrum dн (ppm) 6.41 (1H, d, J 10 Hz), 7.82 (1H, dd, J 2 Hz, 10 Hz) and 8.51 (1H, d, J 2Hz). In each case, which isomer is represented here? The bonds sticking into the centre of the ring can be to any carbon atom. Note: COOH proton is not indicated in the spectra MeO HO₂C CO2H MeO dimethoxybenzoic acid coumalic acidarrow_forwardCompounds A and B are isomers having the molecular formula C4H8O3. Identify A and B on the basis of their 1H NMR spectra.Compound A: δ 1.3 (3H, triplet); 3.6 (2H, quartet); 4.1 (2H, singlet); 11.1 (1H, broad singlet)Compound B: δ 2.6 (2H, triplet); 3.4 (3H, singlet); 3.7 (2H triplet); 11.3 (1H, broad singlet)arrow_forward
- A compound with the molecular formula shown below exhibits a 1H NMR spectrum with only one signal. Deduce the structure in each case. (a) C5H10arrow_forward1 (a) In the following reactions, CI (1) LIAIH, A (2) H20 MCPBA (i) Draw the structure of compounds A and B. (ii) For each reaction, explain the type of reaction involved. (iii) Explain the successful transformation of compound A using mass spectra. (b) Complete the following reactions by filling in missing reactants or product. (i) (1) O3 (2) CH;SCH3 (ii) он (CH3)3(COOH) D Ti(OCH(CH3)2l4 (-)-DETarrow_forwarda) b) Can these three molecules shown below be distinguished by ¹H NMR spectroscopy when the NMR spectrum is recorded in anhydrous (water-free) CDCI3? Give reasons for your answer. NH₂ Can these three molecules shown below be distinguished by ¹H NMR spectroscopy when the NMR spectrum is recorded in deuterated water (D₂O)? Give reasons for your answer. NH₂arrow_forward
- 11. (4) compound X has a molecular formula of C6H8O2, and gave two peaks in its C NMR spectrum but just one in its 1H NMR spectrum (2.5 ppm), IR shows intense absorption peak at 1700 cm provide a structure for compound X.arrow_forwardWhen compound A (C5H12O) is treated with HBr, it forms compound B (C5H11Br). The 1H NMR spectrum of compound A has a 1H singlet, a 3Hdoublet, a 6H doublet, and two 1H multiplets. The 1H NMR spectrum of compound B has a 6H singlet, a 3H triplet, and a 2H quartet. Identifycompounds A and B.arrow_forwardTreatment of compound E (molecular formula C4H8O2) with excess CH3CH2MgBr yields compound F (molecular formula C6H14O) after protonation with H2O. E shows a strong absorption in its IR spectrum at 1743 cm-1. F shows a strong IR absorption at 3600–3200 cm-1. The 1H NMR spectral data of E and F are given. What are the structures of E and F?Compound E signals at 1.2 (triplet, 3 H), 2.0 (singlet, 3 H), and 4.1 (quartet, 2 H) ppmCompound F signals at 0.9 (triplet, 6 H), 1.1 (singlet, 3 H), 1.5 (quartet, 4 H), and 1.55 (singlet, 1 H) ppmarrow_forward
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